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Anarel [89]
2 years ago
12

What is the speed of light in air ?

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ty! ~​
Physics
2 answers:
VikaD [51]2 years ago
6 0

Answer:

the speed of light in air is 3*10⁸m/s.

hichkok12 [17]2 years ago
4 0

Answer:

the speed of light in air is about 299,000,000 and 3×10⁸ m/s

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What is the output voltage from a step up transformer with 25 turns in the primary coil and 75 turns in the secondary coil if th
Greeley [361]

Answer:

360 V

Explanation:

We can use the transformer equation:

\frac{V_p}{N_p}=\frac{V_s}{N_s}

where

V_p is the primary (input) voltage

N_p is the number of turns in the primary coil

V_s is the secondary (output) voltage

N_s is the number of turns in the secondary coil

In this problem,

V_p = 120 V\\N_p = 25\\N_s = 75

Substituting into the equation, we can find the output voltage:

V_s = N_s \frac{V_p}{N_p}=(75)\frac{120}{25}=360 V

7 0
2 years ago
What is the increase in pressure required to decrease volume of mercury by 0.001%
REY [17]

Answer:

Explanation:

Using Boyles law

Boyle's law states that, the volume of a given gas is inversely proportional to it's pressure, provided that temperature is constant

V ∝ 1 / P

V = k / P

VP = k

Then,

V_1 • P_1 = V_2 • P_2

So, if we want an increase in pressure that will decrease volume of mercury by 0.001%

Then, let initial volume be V_1 = V

New volume is V_2 = 0.001% of V

V_2 = 0.00001•V

Let initial pressure be P_1 = P

So,

Using the equation above

V_1•P_1 = V_2•P_2

V × P = 0.00001•V × P_2

Make P_2 subject of formula by dividing be 0.00001•V

P_2 = V × P / 0.00001 × V

Then,

P_2 = 100000 P

So, the new pressure has to be 10^5 times of the old pressure

Now, using bulk modulus

Bulk modulus of mercury=2.8x10¹⁰N/m²

bulk modulus = P/(-∆V/V)

-∆V = 0.001% of V

-∆V = 0.00001•V

-∆V = 10^-5•V

-∆V/V = 10^-5

Them,

Bulk modulus = P / (-∆V/V)

2.8 × 10^10 = P / 10^-5

P = 2.8 × 10^10 × 10^-5

P = 2.8 × 10^5 N/m²

3 0
2 years ago
For this situation to demonstrate a balanced force, how much force must Omar apply? (In the picture, Sam is pushing a box to the
11111nata11111 [884]
The answers 10N as it equals it out
3 0
3 years ago
Read 2 more answers
A person carries a plank of wood 1.6 m long with one hand pushing down on it at one end with a force F1 and the other hand holdi
Elis [28]

Answer: 115.52\ N

Explanation:

Given

Length of plank is 1.6 m

Force F_1 is applied on the left side of plank

Force F_2 is applied 43 cm from the left end O.

Mass of the plank is m=13.7\ kg

for equilibrium

Net torque must be zero. Taking torque about left side of the plank

\Rightarrow mg\times 0.8-F_2\times 0.43=0\\\\\Rightarrow F_2=\dfrac{13.7\times 9.8\times 0.8}{0.43}\\\\\Rightarrow F_2=249.78\ N

Net vertical force must be zero on the plank

\Rightarrow F_1+W-F_2=0\\\Rightarrow F_1=F_2-W\\\Rightarrow F_1=249.78-13.7\times 9.8\\\Rightarrow F_1=115.52\ N

8 0
2 years ago
A doppler effect occurs when a source of sound moves. True or False
Shtirlitz [24]
<h2>Answer: True </h2>

The <u>Doppler effect</u> refers to the change in a wave perceived frequency when the emitter of the waves, and the receiver (or observer in the case of light) move relative to each other.

In other words, it is the variation of the frequency of a wave due to the relative movement of the source of the wave with respect to its receiver.

It should be noted that this effect  bears its name in honor of the Austrian physicist <u>Christian Andreas Doppler</u>, who in 1842 proposed the existence of this effect for the case of light in the stars. Another important aspect is that the effect occurs in all waves (including light and sound). However, it is more noticeable to humans with sound waves.

4 0
2 years ago
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