Answer:
C. resonating
an object being forced to vibrate at its natural frequency creates resonance
Answer:
a) Ffloor = 616.56[N]
b) Ffloor = 484.16 [N]
Explanation:
In order to solve this problem, we must first make a free body diagram. In this free body diagram include forces, as well as acceleration.
Then after the free body diagram, we perform a force analysis by means of Newton's second law, where the upward forces and even the upward acceleration will be taken as positive.
ΣF = m*a
where:
F = force [N] (units of Newtons]
m = mass [kg]
a = acceleration [m/s²]
g = gravity acceleration = 9,81 [m/s²]
a)

![F_{floor} -(56*9.81)=56*1.2\\F_{floor}= 616.56[N]](https://tex.z-dn.net/?f=F_%7Bfloor%7D%20-%2856%2A9.81%29%3D56%2A1.2%5C%5CF_%7Bfloor%7D%3D%20616.56%5BN%5D)
b) Using Newton's second law we have.
![F_{floor}-m*g= -m*a\\F_{floor}=-m*a+m*g\\F_{floor} = -(56*1.2) + (56*9.81)\\F_{floor} = 484.16 [N]](https://tex.z-dn.net/?f=F_%7Bfloor%7D-m%2Ag%3D%20-m%2Aa%5C%5CF_%7Bfloor%7D%3D-m%2Aa%2Bm%2Ag%5C%5CF_%7Bfloor%7D%20%3D%20-%2856%2A1.2%29%20%2B%20%2856%2A9.81%29%5C%5CF_%7Bfloor%7D%20%3D%20484.16%20%5BN%5D)
Answer:
Velocity v = 120 km/h
Time t = 30 s
Let Distance be d
First, we need to convert 120 km/h into m/s
1 km/h = (1000m)/(3600 s) = 5/18 m/s
So, 120 km/h = 120×5/18 m/s
So, v = 200/6 m/s
Now, velocity = distance/time
So d = v×t
So, d = (200/6) × 30
So, d = 1000 m
So, d = 1 km
Thus, distance travelled is 1 km
Explanation:
Amperage (or Amps) in a Series Circuit
The equation V = I/R.
As per the the question the sound source is the mosquito.
the mosquito produces the sound with the help of its wings
as per the question the wings vibrate at the rate of 500 vibrations per second.
we have been asked to calculate the time period of vibration.
we know that that time period is the reciprocal of frequency of vibration
hence time period [T]=
=
=
=0.002 second
hence the time period of the vibration of the wings of the mosquito is 0.002 second.