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3 years ago

Question 6 of 15

Physics

1 answer:

ladessa [460]3 years ago

6 0

Answer: A) True, you are correct

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Explanation:

Power in physics is defined as

power = (change in work)/(change in time)

which shows that power is basically the rate of work done. We can think of it like a speed of sorts.

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For example, if you apply 100 joules of work over 2 seconds, then,

power = (100 joules)/(2 seconds)

power = (100/2) joules per second

power = 50 watts

A watt is defined to be a joule per second, and it's often used to measure how much electricity is consumed, but it has broader uses in physics as well.

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A solar cooker, really a concave mirror pointed at the Sun, focuses the Sun's rays 13.8 cm in front of the mirror. Part A What i

shepuryov [24]

From the concept of optics on a curvature of a spherical mirror, the proportion for which the focal length is equivalent to half the radius of curvature is fulfilled. Mathematically this is

$f = \frac{R}{2}$

Here,

f = Focal Length

R = Radius

Rearranging to find the radius we have,

$R = 2f$

Replacing with our values,

R = 2(13.8cm)

R = 27.6cm

Therefore the radius of the spherical surface from which the mirror was made is 27.6cm

6 0

3 years ago

Check my work please

Amiraneli [1.4K]

We can use the ideal gas equation which is expressed as PV = nRT. At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

T1/P1 = T2/P2

P2 = T2 x P1 / T1

P2 = 273 x 340 / 713

P2 = 130 kPa

5 0

3 years ago

Please help me this is a test and it needs to be done in a few

Amanda [17]

Answer:

I think A because astroids are stronger than a crash. Hope I helped! :)

Explanation:

7 0

4 years ago

Read 2 more answers

(8c7p26) During spring semester at MIT, residents of the parallel buildings of the East Campus dorms battle one another with lar

likoan [24]

Answer: 1175 J

Explanation:

Hooke's Law states that "the strain in a solid is proportional to the applied stress within the elastic limit of that solid."

Given

Spring constant, k = 102 N/m

Extension of the hose, x = 4.8 m

from the question, x(f) = 0 and x(i) = maximum elongation = 4.8 m

Work done =

W = 1/2 k [x(i)² - x(f)²]

Since x(f) = 0, then

W = 1/2 k x(i)²

W = 1/2 * 102 * 4.8²

W = 1/2 * 102 * 23.04

W = 1/2 * 2350.08

W = 1175.04

W = 1175 J

Therefore, the hose does a work of exactly 1175 J on the balloon

7 0

3 years ago

You are pulling a child in a wagon. The rope handle is inclined upward at a 60∘ angle. The tension in the handle is 20 N.

dem82 [27]

Angle (θ) = 60°
Force (F) = 20 N
Distance (s) = 200 m
Therefore, work done
= Fs Cos θ
= (20 × 200 × Cos 60°) J
= (20 × 200 × 1/2) J
= (20 × 100) J
= 2000 J

Answer:

2000 J

Hope you could get an idea from here.

Doubt clarification - use comment section.

6 0

2 years ago

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