The answer would be 2.5.
hope this helps (;
Circle formula
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius
to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D=

points (-3,2) and (1,5)
D=

D=

D=

D=

D=5
center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
y-2=+/-3
add 2
y=2+/-3
y=5 or -1
the point (-7,5) and (7,-1) lie on this circle
radius=5 units
the points (-7,5) and (-7,1) lie on this circle
9514 1404 393
Answer:
8/7
Step-by-step explanation:

Answer: Second option.
Step-by-step explanation:
By defintion, a Quadratic function is a polynomial of degree 2 and it has the following form:

Therefore, the function given is Quadratic. This is:

The steps to find the roots (or the x-intercepts) of the function, are:
1. You must substitute
:

2. Now, you can factor the Quadratic equation. Choose two numbers whose sum is 6 and whose product is 9. Notice that:

Therefore, you will get a "Double root".
4. So the solution is:
