3 years ago

Is the decimal form of 13/3 a rational number?

Mathematics

1 answer:

Arturiano [62]3 years ago

7 0

I would assume so since it is a repeating decimal.

You might be interested in

Imagine working with a younger sibling or student who is having trouble with the 9 times table. Create an algorithm to help the

Irina-Kira [14]

When 9 is multiplied by a number less than eleven, add 1 to the tens place and subtract 1 from the ones place.

7 0

3 years ago

Read 2 more answers

Teds science class collects aluminum cans to sell to the recycling center. The center pays a fixed amount for each kilogram of a

MArishka [77]

Answer: the answer is 100% t=an

Step-by-step explanation:

7 0

3 years ago

Select the correct answer.

antiseptic1488 [7]

Answer: Oc. 28

Step-by-step explanation:

5^2=25

3+5^2=3+25=28

4 0

2 years ago

Solve the following equation. Remember to check for extraneous solutions 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

xxMikexx [17]

Answer:

-1, 2, 6

Step-by-step explanation:

We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

Now, we have, $\frac{1}{x-6} +\frac{x}{x-2} = \frac{4}{x^{2}-8x+12 }$

⇒ $\frac{(x-2)+x(x-6)}{(x-2)(x-6)} = \frac{4}{x^{2}-8x+12 }$

⇒ $\frac{x-2+x^{2}-6x }{(x-2)(x-6)} =\frac{4}{(x-2)(x-6)}$

⇒ $\frac{(x-2)(x-6)}{x^{2}-5x-2 }=\frac{(x-2)(x-6)}{4}$

⇒ $(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$

⇒ $(x-2)(x-6) =0$ or, $[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$

If, (x-2)(x-6) =0, then x=2 or x=6

If, $[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0$ , then $x^{2} -5x-2=4$

and (x-6)(x+1) =0

Therefore, x=6 or -1

So the solutions for x are -1, 2 6. (Answer)

4 0

3 years ago

You look good today, and don’t let people tell you other wise (:

Tamiku [17]

Answer:

Thank You. Have a wonderful day

Step-by-step explanation:

5 0

2 years ago