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adell [148]
3 years ago
8

Plz plz plz, HELP!!!! I will give u brainlylist

Mathematics
1 answer:
melamori03 [73]3 years ago
3 0

Answer:

AB ,AE

Step-by-step explanation:

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A large rectangular swimming pool is 1,000 feet long, 100 feet wide, and 10 feet deep. The pool is filled to the top with water.
MArishka [77]

Answer:

It's a simple question. This swimming pool is basically a rectangular cuboid. Length x Width x Height = how much water it will hold.

Water = 1000000 feet^(3)

Step-by-step explanation:

1000 x 100 x 10 = 1000000 feet^(3)

or you could just converted to meters cube which should be 28316.85 (ish).

8 0
3 years ago
How can i find the area of square and a rectangle
Vinil7 [7]
Multiply (length) times (width). For a square, both numbers will be the same.
8 0
3 years ago
Read 2 more answers
Rewrite the following equation in slope-intercept form.<br><br> 3x − 11y = 19
Law Incorporation [45]

Answer:

y = 3/11(x) - 19/11

Step-by-step explanation:

Step 1: Subtract 3x from both sides.

  • 3x-11y-3x=19-3x
  • -11y=-3x+19

Step 2: Divide both sides by -11.

  • -11y/-11=(-3x+19)/-11
  • y=\frac{3}{11}x-\frac{19}{11}

Therefore, the answer is y = 3/11(x) - 19/11.

8 0
2 years ago
How do u factor out the coefficient of the variable??? -6z + 12 equals what
Bezzdna [24]
-6z+ 12
= -6(z -2) (distributive property)

The final answer is -6(z -2)~

7 0
3 years ago
Need help with #1 #4 #7 plz giving 15 points
valentina_108 [34]

Answer:

Q1:  p = - 33

Q2: d = - 99

Q3: t = - 13

Step-by-step explanation:

Q1: $ \textbf{-} \frac{\textbf{p}}{\textbf{3}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{8} \hspace{1mm}  \textbf{=} \hspace{1mm} \textbf{3}

We solve this taking LCM.

We get: $ \frac{-p - 24}{3} = 3 $

$ \implies - p - 24 = 9 $

$ \implies \textbf{p} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 33} $

Q4: $ \frac{\textbf{d}}{\textbf{11}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{4} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 13} $

Again we proceed like Q1 by taking LCM.

We get: $ \frac{d - 44}{11} = - 13 $

$ \implies d - 44 = - 13 \times 11 = - 143 $

$ \implies d = - 143 + 44 $

$ \implies \textbf{d} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 99} $

Q7: 5t + 12 = 4t - 1

We club the like terms on either side.

$ \implies 5t - 4t = - 1 - 12 $

$ \implies (5 -4)t = - 13 $

$ \implies \textbf{t} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 13} $

Hence, the answer.

7 0
3 years ago
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