the total area of sections 1 and 2 is 48 square units !
<u>Step-by-step explanation:</u>
Here we have , The triangle and the rectangle have the same base, b, and height, h. If the area of the triangle is 48 square units,We need to find what is the total area of sections 1 and 2 . Let's find out:
According to question , we have a triangle with same base and height as of rectangle inside a rectangle ! Following are the parameters of rectangle:
but , Area of rectangle = 
. Also , Area of triangle :
⇒ 
⇒ 
So , Area of rectangle = . Total area of section 1 & 2 is given by :
⇒ 
⇒ 
Therefore , the total area of sections 1 and 2 is 48 square units !
Answer:
a
Step-by-step explanation:
Answer:
A (3,0)
Step-by-step explanation:
The vertex is half way between the zeros
Add the zeros together and divide by 2
(2+4)/2 = 6/2 =3
The vertex is at x=3
Answer:
(5 + √115)/15 or (5 - √115)/15
Step-by-step explanation:
4/5x+4/3 = 2x
Multiply each term by the least common multiple of the denominators (15x)
12 + 20x = 30x²
Move all the terms to the left-hand side.
-30x² + 20x + 12 = 0
Multiply each term by -1
30x² - 20x - 12 = 0
Remove the common factor (2)
15x² - 10x - 6 = 0
Solve by using the quadratic formula
a = 15, b = -10, c = -6
x = (5 + √115)/15 or x = (5 - √115)/15
Answer:
It is always a strait line going up.
Step-by-step explanation:
