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3 years ago

I need help with this

Mathematics

2 answers:

Alex777 [14]3 years ago

7 0

The last one is not a function
Explanation
It’s not a function because there are two nines meaning it repeats
Hope this helped

erastova [34]3 years ago

4 0

Answer:

All of them are functions

Step-by-step explanation:

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HELP ME PLEASE, I'D LIKE TO UNDERSTAND HOW TO DO THIS TOO SO I'LL GIVE BRAINLY FOR THE RIGHT ANSWER WITH GOOD AND UNDERSTANDING

umka2103 [35]

Answer:

34 goes in the blank.

Step-by-step explanation:

Triangle ABC is congruent to triangle TUV implies the following:

Angle A is congruent to angle T.

Angle B is congruent to angle U.

Angle C is congruent to angle V.

Side AB is congruent to side TU.

Side BC is congruent to side UV.

Side CA is congruent to side VT.

Note: Order tells you everything in a congruence statement.

Since side BC is congruent to UV, then the measure of side BC is equal to the measure of side UV.

8x+2=7x+6

Subtract 7x on both sides:

1x+2=6

x+2=6

Subtract 2 on both sides:

x=6-2

x=4

So if x=4, then the measure of side BC is 8x+2=8(4)+2=32+2=34.

So the measure of BC is 34 cm.

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4 years ago

A percent is a way of a expressing a part out of 100. Remember learning about ratios and how they compare quantities? A part-to-

neonofarm [45]

Answer:A

Step-by-step explanation:

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3 years ago

Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

5 0

3 years ago

Determine the sign of the some of negative 8 + 11

AVprozaik [17]

Answer:

positive 3

Step-by-step explanation:

-8 + 11 is 3. the other way you can think of it is by subtracting 8 from 11.

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3 years ago

Read 2 more answers

Will give brainiest & other. Help please!

alina1380 [7]

Answer:

y= 1x

Step-by-step explanation:

6 0

3 years ago