Hey there!
It’s very much impossible to make this equation without it being an exponent because the result has an exponent in it itself
x⁴ × x²
= (x × x × x × x) + (x × x)
≈ x⁴ ⁺ ²
≈ x⁶
Therefore, the answer should be: x⁶
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
Answer:
The correct options are;
A. Construct a perpendicular bisector of the diameter AB
D. Use the compass to draw a circle centered at point C
E. Use the compass to draw two arcs of the same radius centered at point C
F. Use the straightedge to draw diameter AB of the circle
G. Use the straightedge to draw lines connecting the endpoints of the two diameters
Step-by-step explanation:
To draw an inscribed square of a circle, the circle is first constructed. The diameter of the circle is drawn with a straight edge to find the first two vertices of the intended inscribed square. The perpendicular bisector of the diameter is then drawn intersecting the circumference to provide the other two vertices of the square.
The straightedge is then used to draw lines that connect the endpoints of the two diameters to form the inscribed square of the circle.
Answer:
5/6
Step-by-step explanation:
Its the only fraction that has 0.833333...
Answer:
The population of interest for this student is the students whom are enrolled in statistics classes.
Step-by-step explanation:
Sampling
This is a common statistics practice, when we want to study something from a population, we find a sample of this population.
For example:
I want to estimate the proportion of New York state residents who are Buffalo Bills fans. So i ask, lets say, 1000 randomly selected New York state residents wheter they are Buffalo Bills fans, and expand this to the entire population of New York State residents.
The population of interest are all residents of New York State.
A simple random sample of 500 students was selected from all the students enrolled in statistics classes.
This means that the population of interest for this student is the students whom are enrolled in statistics classes.
