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maw [93]
3 years ago
14

a man can row a boat at 4 km per hour in still water. he rolls the boat two kilometre upstream and 2 kilometre back to a startin

g place in 2 hours how fast is the stream flowing​
Physics
2 answers:
stiv31 [10]3 years ago
5 0

Answer:

I would say since it is still water the stream flow is 0km/h. Especially because he needs the same time upstream as He does down stream.

FromTheMoon [43]3 years ago
3 0

Answer:

sorry I don't give answers

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Two 13 cm -long thin glass rods uniformly charged to +11nC are placed side by side, 4.0 cm apart. What are the electric field st
DedPeter [7]

Answer:

E1  = 10.15 * 10^4 N/C

E2 = 0

E3 = 10.15 *10^4 N/C

Explanation:

Given data:

Two 13 cm-long thin glass rods ( L ) = 0.13 m

charge (Q)  = +11nC

distance between thin glass rods   = 4 cm .

<u>Calculate the electric field strengths </u>

electric charge due to a single glass rod in the question ( E ) = \frac{Q}{2\pi e_{0}rL }

equation 1 can be used to determine E1, E2 and E3 because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced

applying equation 1 to determine E1

E1 = \frac{Q}{2\pi e_{0}rL } ( \frac{1}{0.01} - \frac{1}{0.03} )    ( distance from 1 rod is 0.01 m and from the other rod is 0.03 )

   = \frac{11*10^{-9} }{2*3.14*8.85*10^{-12}*0.13 } ( 66.67 )

   = 10.15 * 10^4 N/C

applying equation 1 to determine E2

E2 = \frac{Q}{2\pi e_{0}rL }( \frac{1}{0.02} - \frac{1}{0.02} )

therefore E2 = 0

E1 = E3

hence E3 = 10.15*10^4 N/C

4 0
3 years ago
Billy drops a water balloon from the roof of his house. Since the balloon began with an original velocity of zero how far above
VashaNatasha [74]
T=2,5s
a=g≈10m/s²

h=s=?

s= \frac{1}{2} at^2 \Leftrightarrow h=\frac{1}{2}gt^2=\frac{1}{2}*10m/s^2 *(2,5s)^2=5m/s^2* \frac{25}{4} s^2=\boxed{31,25m}



"Non nobis, Domine, non nobis, sed Nomini tuo da gloriam."


Regards M.Y.
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Any type of wetland that has been developed or maintained by humans for uses such as aquaculture, irrigation, or water storage.

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