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steposvetlana [31]
4 years ago
15

Which statement accurately describes which subatomic particles are involved in nuclear and chemical reactions?

Physics
1 answer:
Vanyuwa [196]4 years ago
6 0
(a) option is right answer
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What does hypothesis mean
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Hypothesis means <span>a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation</span>
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The process by which we use the senses and instrument's to gather information is known as_____​
Assoli18 [71]

Observation– the process of using the five senses to gather information

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3 years ago
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A certain automobile is 6.0 m long if at rest. If it is measured to be 4.8 m long while moving, its speed is:
tatuchka [14]

Answer:

1.8*10^8m/s

Explanation:

Using

L= lo√1-v²/c²

So making v subject we have

V= c√1-4.8²/6²

V= 0.6*c

V= 0.6*3E8m/s

V= 1.8*10^8m/s

7 0
3 years ago
The journey of an electron through an external circuit involves a long and slow zigzag path that is characterized by losses in e
Kitty [74]

Answer:

d_{b} = 2 d_{a}

Explanation:

The electrical resistance for a cylindrical wire is described by the expression

         R = ρ L / A

The area of ​​a circle is

     A = π r²

     r = d / 2

     A = π d²/4

We substitute

      R = ρ L  4 /π d²

Let's apply this expression to our case, they indicate that the resistance of wire A is 4 times the resistance of wire B

    R_{a} = 4 R_{b}

We substitute

    ρ  4/π d_{a}² = 4 (ρ  4/π d_{b}²)

    1 / d_{a}² = 4 / d_{b}²

     d_{a} = d_{b} / 2

4 0
3 years ago
What is the velocity of a proton that has been accelerated by a potential difference of 15 kV? (i)\:\:\:\:\:9.5\:\times\:10^5\:m
andre [41]

Answer:

Velocity of a proton, v=1.7\times 10^6\ m/s    

Explanation:

It is given that,

Potential difference, V=15\ kV=15\times 10^3\ V

Let v is the velocity of a proton that has been accelerated by a potential difference of 15 kV.

Using the conservation of energy as :

\dfrac{1}{2}mv^2=qV

q is the charge of proton

m is the mass of proton

v=\sqrt{\dfrac{2qV}{m}}

v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\ C\times 15\times 10^3\ V}{1.67\times 10^{-27}\ kg}

v=1695361.75\ m/s

v=1.69\times 10^6\ m/s

or

v=1.7\times 10^6\ m/s

So, the velocity of a proton is 1.7\times 10^6\ m/s. Hence, this is the required solution.

8 0
4 years ago
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