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steposvetlana [31]
4 years ago
15

Which statement accurately describes which subatomic particles are involved in nuclear and chemical reactions?

Physics
1 answer:
Vanyuwa [196]4 years ago
6 0
(a) option is right answer
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if the kinetic and potential energy in a system or equal to the potential energy increases what happens as a result
8090 [49]

Answer:If the kinetic and potential energy in a system are equal, then the potential energy increases. ... Stored energy decreases. Energy of motion decreases. Total energy decreases

Explanation:

8 0
3 years ago
Emanuel Zacchini, the famous human cannonball of the Ringling Bros. and Barnum &
weqwewe [10]

Answer:

We have that Assuming No air resistance,the initial horizontal velocity of the cannonball is

From the question we are told that

A cannonball is shot from a cannon at a launch angle of 35 and an initial velocity of 147 m/s

Generally the equation for the horizontal velocity  is mathematically given as

Therefore

Therefore Assuming No air resistance,the initial horizontal velocity of the cannonball is For more information on this visit

Explanation:

4 0
3 years ago
Check my math please? GPE and Power lab
harina [27]
Cases A and B are all correct.

In Case C, the GPE is incorrect. 
(But then, the power and HP have been correctly calculated
from the incorrect value of GPE, so we can't gig you too bad.) 
6 0
3 years ago
After fixing a flat tire on a bicycle you give the wheel a spin. If its initial angular speed was 6.36 rad/s and it rotated 14.7
lesya692 [45]

To solve this problem we will apply the concepts related to the cinematic equations of angular motion. On these equations, angular acceleration is defined as the squared difference of angular velocity over twice the radial displacement. This is mathematically:

\alpha = \frac{\omega^2-\omega_0^2}{2\theta}

Our values are,

\text{Initial angular velocity} = \omega_0 =6.36 rad/s

\text{Final angular velocity} =  \omega =0

\text{Angular displacement} =  \theta = 14.7rev = 29.4\pi rad

Replacing,

\alpha = \frac{- 6.36^2}{29.4\pi}

\alpha = -0.43rad/s^2

Therefore the angular acceleration is -0.43rad/s^2

4 0
3 years ago
A 500 kg car is at rest at the top of a 72 m high hill. The car rolls to the bottom of the hill. At the bottom of the hill, the
rjkz [21]

Explanation: Solution

1.

Gravitational potential energy

U=mgh=500*9.8*50

U=245000 J

2.

Kinetic energy is present at bottom of the hill

K=(1/2)mV2=(1/2)*500*27.82

K=193210 J

3.

Work done by friction

W=193210-245000=-51790 J

3 0
3 years ago
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