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rjkz [21]
3 years ago
6

A beam of ultraviolet radiation, with frequency

Physics
1 answer:
andreyandreev [35.5K]3 years ago
6 0

To develop this problem, we will apply Einstein's relationship which is in charge of the work done with the kinetic energy of the body versus the total energy of the system.

The energy can be calculated as

E = hf

Here,

h = Planck's Constant

f = Frequency

Our values are given as,

f = 2.78*10^{15} Hz ,

W = 3.80 eV

Therefore the Energy is

E = hf

E = 6.625*10^{-34}J\cdot s(2.78*10^{15}Hz)

E = 1.84*10^{-18}J \rightarrow 1 J = 6.242*10^{18}eV

Then,

E = 11.48eV

Applying the Einstein Relation we have that

E = W+KE

KE = E -W

KE = 11.48eV-3.80 eV

KE = 7.68eV

Therefore the maximum  kinetic energy for an electron dislodged fromthe surface by the radiation is 7.68eV

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Answer:

Helium

Explanation:

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Which statement describes the relationship between the rate of reaction and the temperature?
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an athlete runs 5.4 laps around a circular track that is 400.0 m long. If this takes 540 s, what is the average velocity of the
Slav-nsk [51]

Answer:

Average velocity is 0.296 m/s.

Average speed is 4.0  m/s.

Explanation:

Given:

Distance of the circular track is, D=400.0\ m

Number of laps ran is, n=5.4

Time taken for the run is, t=540\ s

Now, total distance covered in 5.4 laps = D_T=D\times n=400\times 5.4=2160\ m

Also, since the path is a circle, the final position of the athlete after 5.4 laps will be 0.4 of 400 m ahead of the starting point.

Distance covered in 0.4 laps is, \textrm{Displacemet}=0.4\times 400=160\ m

Therefore, the displacement of the athlete will be 160 m as the athlete is 160 m ahead of the starting point and displacement depends on the initial and final points only.

Now, average velocity is given as:

v_{avg}=\frac{\textrm{Displacemet}}{t}=\frac{160}{540}=0.296\ m/s

Average speed is the ratio of total distance covered to total time taken.

So, average speed = \frac{D_T}{t}=\frac{2160}{540}=4\ m/s

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A freight car of mass M contains a mass of sand m. At t = 0 a constant horizontal force F is applied in the direction of rolling
Veronika [31]

Answer:

Amount of linear movement

Explanation:

Our system is defined by the rate of change in mass that

leaves the car \Delta m_ {s} , this happens during a time interval

[t, t + \Delta t], in addition to freight car and sand at time t.

In this way we need to define the two states:

State 1,

consider t, m_ {c} (t) + \Delta m_ {s} and V.

State 2,

consider t + \Delta t, m_ {c} (t), V + V \Delta V

In this state is the mass of sand output, which

is composed of

\Delta m_{s}, V + \Delta V

In this way we define the Linear movement in x, like this:

p_ {x} (t) = (\Delta m_ {s} + m_ {c} (t)) v

p_ {x} (t+\Delta t) = (\Delta m_ {s} + m_ {c} (t)) (v + \Delta v)

m_ {c} (t) = m_ {c, 0} - bt = m_ {c} + m_ {s} -bt

In this way we proceed to obtain the Force

F =\lim_{\Delta t \rightarrow 0} \frac {p_x (t + \Delta t) -p_ {x} (t)} {\Delta t}

F = lim_{\Delta t \rightarrow 0} m_ {c} (t) \frac {\Delta v} {\Delta t} + lim_{\Delta t \rightarrow 0} m_ {s} (t) \frac {\Delta v} {\Delta T}

Since the mass of the second term becomes 0, the same term is eliminated, thus,

F = m_ {c} (t) \frac {dv} {dt}

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V (t) = - \frac {F} {b} ln (\frac {m_c + m_s-bt} {m_c + m_s})

3 0
3 years ago
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