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rjkz [21]
3 years ago
6

A beam of ultraviolet radiation, with frequency

Physics
1 answer:
andreyandreev [35.5K]3 years ago
6 0

To develop this problem, we will apply Einstein's relationship which is in charge of the work done with the kinetic energy of the body versus the total energy of the system.

The energy can be calculated as

E = hf

Here,

h = Planck's Constant

f = Frequency

Our values are given as,

f = 2.78*10^{15} Hz ,

W = 3.80 eV

Therefore the Energy is

E = hf

E = 6.625*10^{-34}J\cdot s(2.78*10^{15}Hz)

E = 1.84*10^{-18}J \rightarrow 1 J = 6.242*10^{18}eV

Then,

E = 11.48eV

Applying the Einstein Relation we have that

E = W+KE

KE = E -W

KE = 11.48eV-3.80 eV

KE = 7.68eV

Therefore the maximum  kinetic energy for an electron dislodged fromthe surface by the radiation is 7.68eV

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What is the difference between muscular endurance and muscular strength? A B or C
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Answer:

Muscular endurance is how many times you can move a weight without getting tired.

Muscular strength is the amount force you can put out.

7 0
3 years ago
A 25kg chair initially at rest on a horizontal floor requires 165 N force to set it in motion. Once the chair is in motion, a 12
bazaltina [42]

The coefficient of static friction between the chair and the floor is 0.67

Explanation:

Given:

Weight of the chair = 25kg

Force = 165 N (F_applied)

Force = 127 N (F_max)

To find: Coefficient of static friction  

The “coefficient of static friction” between a chair and the floor is defined as the ration of maximum force to the normal force acting on the chair  

μ_s=F_{max}/F_{n}  

The F_n is equal to the weight multiplied by its gravity

∴F_{n}=mg  

Thus the coefficient of static friction changes as

μ_s=F_{max}/mg

μ_{s} = =165N/((25kg)\times(9.80 m/s^2 ) )

= 0.67

3 0
3 years ago
a car with a mass of 100 kg is stopped on the side of the road after getting a flat tire. the two people that were riding in the
notsponge [240]

Answer:

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3 0
3 years ago
En el País Vasco los deportistas rurales levantan enormes piedras hasta su hombro. En un concurso , Jose levanta una piedra de 2
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Answer:

Txomin lifted the stone with greater mass. (Txomin levantó la roca con mayor fuerza).

Explanation:

The sportsman that lifts the stone with a greater mass needs a higher force (El deportista que levanta la piedra con mayor masa necesita una mayor fuerza):

José

F = (200\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F = 1961.4\,N

Txomin

F = (220\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F = 2157.54\,N

Txomin lifted the stone with greater mass. (Txomin levantó la roca con mayor fuerza).

5 0
2 years ago
A car moving around a circular track with constant speed (Select all that apply.) has an acceleration with a direction that cann
BARSIC [14]

Answer:

Explanation:

Has an acceleration directed towards center of its path

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