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eimsori [14]
3 years ago
5

Calculated the gravitational potential energy of a 93.0 kg sky diver who is 550 m above the ground

Physics
1 answer:
Alchen [17]3 years ago
4 0
Equation for Gravitation Potential Energy...
GPe = m·g·h
where m = mass in kg = 93.0 kg
g = force of gravity = 9.81 m/s²
<span>h = height in meters = 550m
</span>
GPe = mgh
GPe = (93)(9.81)(550)
GPe = 501781.5 Joules (J)
GPe = 5.02 x 10⁵ J (rounded & in scientific notation)

Therefore, the gravitational potential energy of a person of mass 93.0kg who is 550m above the ground is GPe = 501781.5 Joules (J)

Hope this helps! 
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Answer:

Option D

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BlackZzzverrR [31]

Answer:

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B. The silica cylinder of a radiant wall heater is 0.6 m long
SIZIF [17.4K]

So,  If the silica cyliner of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K

To estimate the operating temperature of the radiant wall heater, we need to use the equation for power radiated by the radiant wall heater.

<h3>Power radiated by the radiant wall heater</h3>

The power radiated by the radiant wall heater is given by P = εσAT⁴ where

  • ε = emissivity = 1 (since we are not given),
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  • A = surface area of cylindrical wall heater = 2πrh where
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  • h = length of heater = 0.6 m, and
  • T = temperature of heater

Since P = εσAT⁴

P = εσ(2πrh)T⁴

Making T subject of the formula, we have

<h3>Temperature of heater</h3>

T = ⁴√[P/εσ(2πrh)]

Since P = 1.5 kW = 1.5 × 10³ W

Substituting the values of the variables into the equation, we have

T = ⁴√[P/εσ(2πrh)]

T = ⁴√[1.5 × 10³ W/(1 × 6 × 10⁻⁸ W/m²-K⁴ × 2π × 6 × 10⁻³ m × 0.6 m)]

T = ⁴√[1.5 × 10³ W/(43.2π  × 10⁻¹¹ W/K⁴)]

T = ⁴√[1.5 × 10³ W/135.72  × 10⁻¹¹ W/K⁴)]

T = ⁴√[0.01105 × 10¹⁴ K⁴)]

T = ⁴√[1.105 × 10¹² K⁴)]

T = 1.0253 × 10³ K

T = 1025.3 K

So, If the silica cylinder of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K

Learn more about temperature of radiant wall heater here:

brainly.com/question/14548124

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