Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.
The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:
27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u
The actual mass of the nucleus of 60-Co is 59.933820 u.
Mass defect: 60.497220 u - 59.933820 u = 0.563400 u
The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2
(0.563400 u)*(931.5 MeV/u) = 524.807 MeV
°Alternate interior angles are equal
°Corresponding angles are equal
°Vertically opposite angles are equal
°Angles on the same side of tranversal are supplementary
To find the perimeter you need to add all 3 sides
Answer:
1. x less than or equal to 1/3
2. x is less than 1
3. x is greater than 6
4. x is less than -2
Step-by-step explanation:
