First we find k by using the two values given:
P=Ae^(kt), 8 years between-->t=8
199 = 195•e^(8k)
Log 199 = Log [195•e^(8k)]
Log 199 = Log 195 + 8k
8k = Log 199 - Log 195
k = 0.00882/8 = .0011
Next, we plug the new data in using this k:
14 years between 2002-2016-->t=14
P = Ae^my
P = 199mi.•e^(14•.0011)
P = 199mi.•e^(.0154)
P = 199mi. • 1.0155 = 202,088,000
Answer:
4 hours and 7 hours
Step-by-step explanation:
Marcus = x hours
Donnell = x + 3 hours
Total = 11 hours
- x + x + 3 = 11
- 2x + 3 = 11
- 2x = 8
- x = 4
So Marcus practiced 4 hours and Donnell practiced 7 hours
F(4) = 5 because (x, y) = (4, 5)
a function is normally
