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givi [52]
3 years ago
6

How many moles are in 2.126 mg of H2O2

Chemistry
1 answer:
mario62 [17]3 years ago
5 0

Explanation:

According to the formula there are 2 moles of hydrogen and 2 moles of oxygen in each hydrogen peroxide molecule. So hydrogen peroxide has a molecular weight of 34.0146 grams per mole.

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In the metric system, the ________ describes the relationship of each unit to the base unit.
gavmur [86]

Answer:

prefix

Explanation:

4 0
3 years ago
Web_assetHIDE QUESTION<br><br><br> 7- When an organism reproduces asexually, it usually has
adelina 88 [10]
<span>Only one parent and the same chromosome
number as the parent.

</span>
5 0
3 years ago
Compound W, C8H17Br, and X, C8H17Cl, are products of the radical bromination (W), and chlorination (X), of 2,4-dimethylhexane. W
oksian1 [2.3K]

Answer:

The possible structures are shown in figure.

Explanation:

The seven isomers that could be formed from the given compound due to radical halogenation are shown in the figure.

We have mentioned only chlorine as group for showing just the chiral nature of the compound.

A chiral compound has a carbon with all the four groups different from each other.

There are three structures which are chiral (as shown).

W is the brominated product

X is the chlorinated product.

1) W reacts readily in water to form a chiral substitution product Y, C8H17OH.

Reaction of a single enantiomer of W produces a single enantiomer of Y as the only substitution product.: It means that the substitution is SN2 which is possible if the compund is not tertiary.

2) X likewise reacts readily in water though at a slower rate than W; a chiral substitution product Z, C8H17OH, is again formed. Unlike W, however, reaction of a single enantiomer of X produces Z that is nearly racemic.

It means that it will undergo SN1 reaction,. So the alkyl halide must be tertiary.

The possible structures are shown in figure.

5 0
4 years ago
Addition of an excess of lead (II) nitrate to a 50.0mL solution of magnesium chloride caused a formation of 7.35g of lead (II) c
KiRa [710]

Answer:

[Cl⁻] = 0.016M

Explanation:

First of all, we determine the reaction:

Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓  +  Mg(NO₃)₂(aq)

This is a solubility equilibrium, where you have a precipitate formed, lead(II) chloride. This salt can be dissociated as:

           PbCl₂(s)  ⇄  Pb²⁺ (aq)  +  2Cl⁻ (aq)     Kps

Initial        x

React       s

Eq          x - s              s                  2s

As this is an equilibrium, the Kps works as the constant (Solubility product):

Kps = s . (2s)²

Kps = 4s³ = 1.7ₓ10⁻⁵

4s³ = 1.7ₓ10⁻⁵

s =  ∛(1.7ₓ10⁻⁵ . 1/4)

s = 0.016 M

3 0
3 years ago
A 2.5 g sample of french fries is placed in a calorimeter with 500.0 g of water at an initial temperature of 21 °C. After combus
SIZIF [17.4K]
Q=m°C<span>ΔT
=(500g) x (1 cal/g.</span>°C) x (48°C-21°C) = 13500 cal
13500 cal / 1000 = 13.5 kcal

<span>"What is the caloric value (kcal/g) of the french fries?"
13.5 kcal/ 2.5 g = 5.4 kcal/g</span>
8 0
4 years ago
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