Answer:
0.0097 mol·L⁻¹
Explanation:
The balanced equation is
2NOCl ⇌ 2NO₂ + Cl₂
Data:
Your value of Kc is incorrect. It should be
Kc =1.6 × 10⁻⁵
[NOCl] = 0.50 mol·L⁻¹
[NO] = 0.00 mol·L⁻¹
[Cl₂] = 0.00 mol·L⁻¹
Calculations:
1. Set up an ICE table.
2. Calculate the equilibrium concentrations
This is a cubic equation. Some calculators can solve cubic equations, but we can solve it by the method of successive approximations.
We will make changes to the right-hand side until the calculated value of x no longer changes,
(a) 1st approximation
Assume that 2x is negligible compared to 0.50. Then
(b) 2nd approximation
Assume that x= 0.010. Then
(b) 3rd approximation
Assume that x= 0.0097. Then
No change, so x = 0.0097.
[Cl₂] = x mol·L⁻¹ = 0.0097 mol·L⁻¹
Check:
It checks.
The balanced chemical reaction would be
<span>4Fe(s) + 3O2(g) ---> 2Fe2O3(s)
We are given the amount of Fe to be used in the reaction. We use this as the starting point for the calculations. We do as follows:
25.9 g Fe (1 mol / 55.85 g) ( 2 mol Fe2O3 / 1 mol Fe ) (159.69 g / mol ) = 262.48 g Fe2O3 produced</span>
The amount of pressure should be reduced by one half.
Hope this helps! :)