neutralisation is the process of converting an acid or a base into the pH value 7.The 2 things produced r hydrogen gas and a salt.
acid+base=salt+hydrogen gas.This often occured in your stomach. when you have gastroble you are eating tablets which are base and a reation take place with hydrocloric acid in it
hope it helps
Eukariotic cells have nuclei, while prokaryotic cells do not.
Maximum Thrift is a method / philosophy that considers the shortest tree (in number of transformation steps) the best hypothesis about the phylogenetic relationship of a given set of terminals. Transformation step is the cost attributed to the change of character state in a given branch of the tree, be it the change from one nucleotide base to another, amino acids, or the color of an animal's iris. The fewer transformations, the shorter the tree, and therefore the more parsimonious. In this method, what programs do is to investigate as many alternative topologies as possible (or all if their array has less than 25 terminals; see more details below) given their character array. Each will be measured, and the shorter (optimal) trees will be retained as the most parsimonious result.
Answer:
See the answer below
Explanation:
<em>Recall that the law of dilution states that the number of moles before dilution must be equal to the number of moles after dilution.</em>
Mathematically,
molarity x number of moles before dilution = molarity x number of moles after dilution.
For solution A: final molarity = 3 mM, final volume = 2mL, initial molarity of KMnO4 = 10 mM
Applying the equation:
10 x initial volume = 3 x 2
initial volume = 6/10 = 0.6
<u>Hence, Tube A should be made with 0.6 mL of 10 mM KMnO4 stock and 1.4 mL of distilled water to give a solution of 2 mL 3 mM KMnO4.</u>
For solution B:final molarity = 8 mM, final volume = 2 mL, initial molarity = 10 mM
10 x initial volume = 8 x 2
initial volume = 16/10 = 1.6
<u>Hence, Tube B should be made with 1.6 mL of 10 mM KMnO4 stock and 0.4 mL of distilled water to give a solution of 2 mL 8mM KMnO4. </u>
