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kvv77 [185]
3 years ago
11

How can a substance stay at a certain temperature even though it is being heated?​

Chemistry
1 answer:
SOVA2 [1]3 years ago
5 0
The temperature of a certain substance can be seen as the average speed of the atoms or molecules in that substance. In the liquid state of a substance the forces between the atoms or molecules are strong enough to keep them together, however with enough freedom to move, unlike in the solid state. If we would have a closer look at the surface of a liquid from sideways, we would see water molecules jumping out of the water and reentering it again. The lower the water temperature would be the lesser the amount of water molecules leaving the liquid phase would be. If water would be heated up and the temperature will reach 100 degrees C at normal atmospheric pressure, more water molecules would leave the water than reentering. Boiling has started. The temperature of the water remains at 100 degrees C, if the heating continues as the average speed of molecules will not increase, only the rate of molecules leaving the water will increase, until all the water in liquid state has been vapourized. The amount of heat needed to vapourize liquid water is called latent heat. Latent heat is a very important driving factor in the atmosphere and thus the weather.
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WITCHER [35]

Answer:

  91.7°C

Explanation:

We suppose you have a formula to work from. However, that is not supplied with this problem statement, so we looked one up.

The formula in the attachment is supposed to have good accuracy in the temperature range of interest. It gives vapor pressure of water in kPa, not mmHg, so we needed the conversion for that, too.

560 mmHg corresponds to about 74.66 kPa. The attached "Buck equation" formula is used to find the corresponding temperature. The exponential equation could be solved algebraically using logarithms and the quadratic formula, but we choose to find the solution graphically.

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7 0
3 years ago
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JulijaS [17]

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Explanation:

pH = -log [H+ ]

1. 1.0 x 10^-5 M HCl

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2. 0.1 M HNO3

pH = - log (1.0 x 10 ^ -1)

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3. 1.0 x 10^-5 NaOH

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= 2 - log 1 = 2

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Therefore, pH = 14 - 2 = 12

8 0
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3 years ago
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