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sineoko [7]
3 years ago
7

Plz help me show your work​

Mathematics
2 answers:
svetlana [45]3 years ago
6 0

Step-by-step explanation:

5p + 1/2p - 2.75 + 2/3 A

Convert the decimal into a fraction

11/2p - 11/4 + 2/3 a

natka813 [3]3 years ago
5 0

Answer:

Step-by-step explanation:

5p + 1/2 p + 2/3p - 2.75

10/6p - 2.75

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What is the measure of [theta]?
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Need help with 7A plz
Eduardwww [97]
A) area of square = base*height/////Triangle= 0.5*base*height

=(a^1/3*b^3/4)*(a^2/3*b^1/2)+(1/2*a^1/3*b^3/4*a^2/3*b^1/4)
=(a^1*b^5/4)+(1/2*a^1*b^1)
=(a*b^5/4)+(1/2*a*b)

B) a^2+b^2=c^2 (pythagorean theorem)
   ((27^2/3)*(16^1/4))^2 +  (27^1/3)*(16^3/4)   
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     (900)^1/2= 30
hypotenuse= 30

C)( a^2/3*b^1/2)= 36*2(two sides)= 72
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7 0
4 years ago
The lengths of the diagonals of a rhombus are 2x and 10x. What expression gives the perimeter of the rhombus?
True [87]

Answer:

P=4x\sqrt{26}\ units

Step-by-step explanation:

we know that

The sides of a rhombus are all congruent and the diagonals are perpendicular bisectors of each other

so

Applying the Pythagorean Theorem

c^2=a^2+b^2

where

c is the length side of the rhombus      

a and b are the semi-diagonals

we have

a=2x/2=x\ units\\b=10x/2=5x\ units

substitute the values

c^2=x^2+(5x)^2

c^2=26x^2

c=x\sqrt{26}\ units

To find out the perimeter of the rhombus multiply the length side by 4

P=(4)(x\sqrt{26})

P=4x\sqrt{26}\ units

6 0
4 years ago
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