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erastova [34]
3 years ago
12

How many moles of hydrogen atoms are present in 15 moles of C2H6O? Answer in units of mol.

Chemistry
1 answer:
777dan777 [17]3 years ago
3 0
Mol of H atom = 15x6
=90
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A beam of light has a wavelength of 24.0 μm ( μm = 10 -6m). What is its frequency?
vfiekz [6]

Answer:

Frequency = 1.25 ×10¹³ Hz

Explanation:

Given data:

Wavelength of light = 24.0  μm (2.4 ×10⁻⁵ m)

Frequency = ?

Solution:

Formula:

Speed of light = wavelength × frequency

Speed of light /wavelength = frequency

Frequency = 3×10⁸ m /s /2.4 ×10⁻⁵m

Frequency = 1.25 ×10¹³ s⁻¹

s⁻¹ = Hz

Frequency = 1.25 ×10¹³ Hz

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Standard notation for 31,254,000
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4 years ago
Gaseous methane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If of water is produced fro
Nonamiya [84]

Answer:The masses of the reactants and products formed are not included in the question, so we cannot determine the percentage yield of water without knowing the yields of other substances.

However the formulae for percentage yield is;

Percentage yield=experimental yield/theoretical yield X 100

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3 years ago
How does removing trees affect nitrogen cycling in a forest ecosystem?
nikdorinn [45]

Explanation:

The roots of trees in a forest are colonized by symbiotic fungi called mycorrhizae. These fungi are significant nitrogen fixers because they harbor nitrogen-fixing bacteria. They convert atmospheric nitrogen into nitrates and nitrites that can be absorbed by plants. The plants use these forms of nitrogen to build biomolecules such as DNA and amino acids.This nitrogen is transferred up the food chain. Eventually the nitrogen is again recycled by denitrifiers when the organisms die.

Removing trees will disrupt the symbiotic relationship with mycorrhizae, stime the nitrogen cycle in the forest.

Learn More:

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4 0
3 years ago
Read 2 more answers
A 150.0 mL sample of an aqueous solution at 25°C contains 15.2 mg of an unknown nonelectrolyte compound. If the solution has an
inysia [295]

<u>Answer:</u> The molar mass of the unknown compound is 223.2 g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

where,

\pi = osmotic pressure of the solution = 8.44 torr

i = Van't hoff factor = 1 (for non-electrolytes)

M = molarity of solute = ?

R = Gas constant = 62.3637\text{ L torr }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

8.44torr=1\times M\times 62.3637\text{ L. torr }mol^{-1}K^{-1}\times 298K\\\\M=\frac{8.44}{1\times 62.3637\times 298}=4.54\times 10^{-4}M

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 4.54\times 10^{-4}M

Given mass of unknown compound = 15.2 mg = 0.0152 g   (Conversion factor:  1 g = 1000 mg)

Volume of solution = 150.0 mL

Putting values in above equation, we get:

4.54\times 10^{-4}M=\frac{0.0152\times 1000}{\text{Molar mass of unknown compound}\times 150.0}\\\\\text{Molar mass of unknown compound}=\frac{0.0152\times 1000}{150.0\times 4.54\times 10^{-4}}=223.2g/mol

Hence, the molar mass of the unknown compound is 223.2 g/mol

5 0
3 years ago
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