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icang [17]
3 years ago
14

Answer, please!!!!!!

Chemistry
1 answer:
pshichka [43]3 years ago
5 0

Answer:

C. SOIL THAT IS A MIXTURE OF STILT AND CLAY

PLS MAKE ME BRAINLEST!

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Nitrous oxide (n2o), or laughing gas, is commonly used as an anesthetic in dentistry and surgery. how many moles are present in
Gelneren [198K]

Answer is: 0.375 moles are present in 8.4 liters of nitrous oxide at stp.

V(N₂O) = 8.4 L.

V(N₂O) = n(N₂O) · Vm.

Vm = 22,4 L/mol.<span>
n</span>(N₂O) = V(N₂O) ÷ Vm.

n(N₂O) = 8.4 L ÷ 22.4 L/mol.

n(N₂O) = 0.375 mol.<span>
Vm - molare volume on STP.</span>

5 0
3 years ago
Is sisig is homogeneous or heterogeneous​
givi [52]

Answer:

I think its homogeneous

Explanation:

because its all pig, just different parts of the pig

7 0
3 years ago
A piece of an unknown metal has a volume of 19.8 ml and a mass of 210.0 grams. The density of the metal is g/mL A piece of the s
leva [86]

<u>Answer:</u> The density of the metal is 10.60 g/mL and the volume occupied by 86.0 grams is 8.11 mL

<u>Explanation:</u>

To calculate the density of unknown metal, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}       ......(1)

Volume of unknown metal = 19.8 mL

Mass of unknown metal = 210.0 g

Putting values in equation 1, we get:

\text{Density of unknown metal}=\frac{210.0g}{19.8mL}\\\\\text{Density of unknown metal}=10.60g/mL

The density of the metal remains the same.

Now, calculating the volume of unknown metal, using equation 1, we get:

Density of unknown metal = 11.45 /mL

Mass of unknown metal = 86.0 g

Putting values in above equation, we get:

10.60g/mL=\frac{86.0g}{\text{Volume of unknown metal}}\\\\\text{Volume of unknown metal}=8.11mL

Hence, the density of the metal is 10.60 g/mL and the volume occupied by 86.0 grams is 8.11 mL

5 0
3 years ago
Why does metal need to be extracted from an ore before it can be used?
Hunter-Best [27]
Metal ore has other elements in it as well. Also sediment and stone might cover the ore. We don't want to have a phone with sediment on it do we? thus these few reasons are why.
7 0
3 years ago
3. Will the density of aluminum be less or more than the actual value if a student does
dimulka [17.4K]

Answer:

less dense

Explanation:

the reason that the density would be lower is because the air bubbles keep the maximum amount of atoms possible from being in that space. imagine pouring a glass of soda from a freshly opened bottle, at first it looks like there's a lot in the glass but as the bubbles dissipate, there's less and flat soda appears to have even less in the glass. i hope this analogy helped :)

5 0
3 years ago
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