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2 years ago

Which has the larger change hydration in each pair of a)Na+ Or cs+ b)Sr+2 or Rb+ c)Na+ or Cl- d) O-2 or F- e)OH- or SH-

Chemistry

1 answer:

Charra [1.4K]2 years ago

4 0

Answer:

See explanation

Explanation:

The size of the hydration enthalpy of a system depends on the attraction between the ions and the water molecules. Stronger attractions exist between water and smaller ions. The smaller the ion, the higher the hydration enthalpy is.

In the first pair, Na+ is smaller than Cs+ hence Na+ has a larger change in hydration enthalpy.

In the second pair, Sr2+ is smaller than Rb+ hence Sr2+ has a larger change in hydration enthalpy.

In the third pair, Na+ is smaller than Cl- hence Na+ has a larger change in hydration energy.

F- is smaller than O2- hence F- has a larger change in hydration energy.

OH- is smaller than the SH- hence the OH- has a larger change in hydration energy.

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3.00 L of a gas is collected at 35.0°C and 705.0 mmHg. What is the volume at STP?

makvit [3.9K]

Answer:

2.47L

Explanation:

Using the combined gas law equation as follows:

P1V1/T1= P2V2/T2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 705mmHg

P2 = 760mmHg (STP)

V1 = 3.00L

V2 = ?

T1 = 35°C = 35 + 273 = 308K

T2 = 273K (STP)

Using P1V1/T1= P2V2/T2

705 × 3/308 = 760 × V2/273

2115/308 = 760V2/273

Cross multiply

308 × 760V2 = 2115 × 273

234,080V2 = 577,395

V2 = 577,395 ÷ 234,080

V2 = 2.47L

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How is data not actually obtained from the experiment represented in a line graph?

zavuch27 [327]

A colored line, as long as it is one single piece, not broken

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3 years ago

Read 2 more answers

The density of an aqueous solution of nitric acid is 1.64 g/mL and the concentration is 1.85 M. What is the concentration of thi

galina1969 [7]

Answer:

Mass % of the solution = 7.1067 %

Explanation:

Given :

Molarity of nitric acid solution = 1.85 M

Density of the solution = 1.64 g/mL

Molarity of a solution is defined as the number of moles of solute present in 1 liter of the solution.

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Lets, consider the volume of the solution = 1 L

Thus,

Moles of nitric acid present in the solution:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Moles of Nitric acid=Molarity \times {Volume\ of\ the\ solution}$

So,

Moles of Nitric acid = 1.85 moles

Molar mass of nitric acid = 63 g/mol

The mass of Nitric acid can be find out by using mole formula as:

$moles=\frac{Mass\ taken}{Molar\ mass}$

Thus,

$Mass\ of\ Nitric\ acid=Moles \times Molar mass}$

$Mass\ of\ Nitric\ acid=1.85 g \times 63 g/mol}$

Mass of Nitric acid = 116.55 g

Also,

$Density=\frac{Mass}{Volume}$

Given : Density = 1.64 g/mL

Also, 1 L = 10³ mL

Volume of the solution is 1000 mL

So, mass of the solution:

$Mass\ of\ the\ solution=Density \times {Volume\ of\ the\ solution}$

$Mass\ of\ the\ solution=1.64 g/mL \times {1000 mL}$

Mass of the solution = 1640 g

Mass % is defined as the mass of solute in 100 g of the solution. The formula for the calculation of mass % is shown below:

$Mass \% =\frac{Mass\ of\ the\ solute}{Mass\ of\ the\ solution} \times {100}$

So,

$Mass \%=\frac{116.55}{1640} \times {100}$

Mass % = 7.1067 %

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3 years ago

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True because it actually formed I know

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Classify the substances according to the strongest solute-solvent interaction that will occur between the given substances and w

-BARSIC- [3]

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3 years ago