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Andrews [41]
3 years ago
7

A ball is released from a height of 18 m and weighs 19 N . What is the magnitude of the total change in potential energy Δ U as

the ball falls to the ground?
Physics
1 answer:
ozzi3 years ago
6 0

Answer:

The magnitude of the total change in potential energy ΔU as the ball falls to the ground is 342 joules.

Explanation:

It is given that,

Height from which the ball is released, h = 8 m

Weight of the ball, F = 19 N

To find,

The magnitude of the total change in potential energy ΔU as the ball falls to the ground.

Solution,

The energy that is possessed by an object due to its position is called its potential energy. Its formula is given by :

\Delta U=mgh

\Delta U=F\times h

\Delta U=19\ N\times 18\ m

\Delta U=342\ J

So, the magnitude of the total change in potential energy ΔU as the ball falls to the ground is 342 joules. Hence, this is the required solution.

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The largest building in the world by volume is the boeing 747 plant in Everett, Washington. It measures approximately 632 m long
Schach [20]

Explanation:

Given that,

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Since,

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632 m = 2073.49 feet

1 yard= 3 feet

710 yards = 2130 feet

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V=2073.49 \ ft\times 2130\ ft\times 112\ ft

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V=4.94\times 10^8\ ft^3

Also,

V=(4.94\times 10^8\ ft^3)(\dfrac{1\ m}{3.281})^3

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High and low tides are the regular pattern of rising and sinking ocean-water levels. They are caused when the sun's gravity and
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Answer:

D. The moon is closer to Earth than the sun.

Explanation:

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Since gravity variate with the distance:

   

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Where m1 and m2 are the masses of the two objects that are interacting and r is the distance

For example, see the image below, point A is closer to the moon than point b and at the same time the center of mass of the Earth will feel more attracted to the moon than point B. Therefore, that creates a tidal bulge in point A and point B.

The Sun tidal force contributes to the tidal force of the moon over the earth making high tides higher and low tides lower.  

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8 0
3 years ago
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5 0
3 years ago
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If an object falls for 4 seconds, how fast is it going when it hits the ground?
MArishka [77]

Acceleration due to gravity is about 9.8 m/s²

So after every second, the speed increase by 9.8 m/s

After 1 second, the object would fall at a speed of 9.8 m/s

After 2 seconds the object would fall at a speed of 19.6 m/s

So after 4 seconds, the object is going to be at a speed of:

9.8 x 4 = 39.2 m/s

-------------------------------------------------

<u>Answer</u>

39.2 m/s

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