A ball is released from a height of 18 m and weighs 19 N . What is the magnitude of the total change in potential energy Δ U as
1 answer:
Answer:
The magnitude of the total change in potential energy ΔU as the ball falls to the ground is 342 joules.
Explanation:
It is given that,
Height from which the ball is released, h = 8 m
Weight of the ball, F = 19 N
To find,
The magnitude of the total change in potential energy ΔU as the ball falls to the ground.
Solution,
The energy that is possessed by an object due to its position is called its potential energy. Its formula is given by :
So, the magnitude of the total change in potential energy ΔU as the ball falls to the ground is 342 joules. Hence, this is the required solution.
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Answer:
The ball travels with a speed of 1.96 m/s in a North East direction
Explanation:
Based on the law of conservation of linear momentum, we have that
Since this problem involves motion in both the x and y coordinates, we will solve it in the separate coordinates, and then find the resultant as our answer.
Momentum in the x- direction
in the x direction, . this makes
hence we have
Momentum in the y- direction
in the y direction, . this makes
hence we have
The resultant of the two vectors can be found using Pythagoras' theorem
The direction of the resultant vector is found as
Hence the ball moves with a velocity of 1.96m/s in a North East direction
Answer:
Torque,
Explanation:
It is given that,
Length of the wrench, l = 0.5 m
Force acting on the wrench, F = 80 N
The force is acting upward at an angle of 60.0° with respect to a line from the bolt through the end of the wrench. We need to find the torque is applied to the nut. We know that torque acting on an object is equal to the cross product of force and distance. It is given by :
So, the torque is applied to the nut is 34.6 N.m. Hence, this is the required solution.