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Andrews [41]
3 years ago
7

A ball is released from a height of 18 m and weighs 19 N . What is the magnitude of the total change in potential energy Δ U as

the ball falls to the ground?
Physics
1 answer:
ozzi3 years ago
6 0

Answer:

The magnitude of the total change in potential energy ΔU as the ball falls to the ground is 342 joules.

Explanation:

It is given that,

Height from which the ball is released, h = 8 m

Weight of the ball, F = 19 N

To find,

The magnitude of the total change in potential energy ΔU as the ball falls to the ground.

Solution,

The energy that is possessed by an object due to its position is called its potential energy. Its formula is given by :

\Delta U=mgh

\Delta U=F\times h

\Delta U=19\ N\times 18\ m

\Delta U=342\ J

So, the magnitude of the total change in potential energy ΔU as the ball falls to the ground is 342 joules. Hence, this is the required solution.

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A bubble, located 0.200 m beneath the surface in a glass of beer, rises to the top. The air pressure at the top is 1.01x10⁵ Pa.
Cerrena [4.2K]

Answer:

\frac{1.019}{1}

Explanation:

To solve this equation we will have to consider that the bubble is filled with an Ideal Gas and as such we can use the Ideal Gas Law

PV = nRT

Where

P = Pressure

V = Volume

n = Moles

R = Ideal Gas Constant

T  = Temperature

Now since we know that the value for the temperature and moles is constant we can simply use Boyles Law for the two states

P_{1} V_{1} =P_{2} V_{2}

Let us look at the two states

State 1 (at top)

Pressure = 1.01*10^5

Volume = V_{1}

State 2 (at bottom)

Pressure = 1.01*10^5 + dgh

Where

d = Density of liquid (1000 kg/m³)

d = Acceleration due to gravity (9.8 m/s²)

d = Height of liquid (0.200 m)

Pressure = 102,962

Volume = V_{2}

Inputting these values into the Boyles Law

P_{1} V_{1} =P_{2} V_{2}\\ (101000)V_{1} = (102962)V_{2}\\ \frac{V_{1}}{V_{2}} = \frac{102962}{101000} \\  \frac{V_{1}}{V_{2}} = \frac{1.019}{1}

6 0
3 years ago
What term best describes the geologic event taking place in the above illustration?
grigory [225]

u lying you made me get it wrong, for ya'll out there who want the real answer is sea floor spreading

8 0
3 years ago
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You Discover A Beautiful Island Upon Which You May Build Your Own Society. You Make The Rules. What Is The First Rule You Put In
alekssr [168]

Answer: no plastic

Explanation:

4 0
3 years ago
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If your friend drops a chocolate bar to you from a height of 5.0 m above your hands,
Sladkaya [172]

Answer:

<h3>1.01 s</h3>

Explanation:

Using the equation of motion S = ut+1/2gt² to solve the problem where;

u is the initial velocity of the chocolate = 0m/s

t is the time taken

g is the acceleration due to gravity = 9.81m/s²

S is the height of fall = 5.0m

Substituting the given parameter into the formula to get the time t we have;

5 = 0(t)+1/2(9.81)t²

5 = 4.905t²

t² = 5/4.905

t² = 1.019

t = √1.019

t = 1.009 secs

<em>Hence it will take 1.01 secs for me to catch the chocolate bar</em>

6 0
4 years ago
At this rate, how long would it take for two continents 3500 kilometers apart to collide?
meriva

<span>Given:

3,500 kilometers

Find:</span>

 

Years for two continents to collide = ?

 

<span>Solution:

We know that </span>typical motions of one plate relative to another are 1 centimeter per year.

So first, we convert 3,500 km to cm.<span>
</span><span>

</span>

The solution would be like this for this specific problem:

 

1 km = 100,000 cm

3,500 km x 100,000 = 350,000,000 cm

Since we know that 1 cm = 1 year, then that means 350,000,000 cm is equivalent to 350,000,000 years.

 

Therefore, it would take 350 million years for two continents that are 3500 kilometers apart to collide.

<span>
To add, </span>a phenomenon of the plate tectonics of Earth that occurs at convergent boundaries is called the continental collision.

5 0
3 years ago
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