Let's call their parts w,m and s
if will paid 1/3, then m+s=2w (they paid 2/3, which is twice as much as will did)
Now, we know that:
Micah and Sue paid in the ratio 2:3.
this means the 3m=2s
and m=2/3s
Again:
m+s=2w
and we substitute m:
2/3s+s=2w
5/3s=2w// multiply both sides by 3
5s=6w
we also know that s=w+6 (from the last sentence) so we substitute:
5(w+6)=6w
5w+30=6w
30=w
so, Will paid 30, Sue paid 36 (six more than him), Mike paid 24 (24:36 is the same ratio as 2:3, you can check this by dividing both 24 and 36 by 12: you have 2 and 3)
and the total was 30+36+24=90.
We are given
x1 = 10 ft
y1 = 14 ft
x2 = 13 ft
y2 = 9 ft
We are asked to find the distance between the base of the house to the closest treetop.
So,
d1 = √(10² + 14²) = 17.20
d2 √(13² + 9²) = 15.81
The distance is 15.81 ft to the closest treetop which is the tree 13 feet from the base of the house.
Answer:
Colin has <em>8 sheets </em>left for his third class.
Step-by-step explanation:
Given that:
Total Number of pieces of papers =
Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad
Writing the equation:
Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.
Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class
So, the answer is:
Colin has <em>8</em> <em>sheets </em>left for his third class.
Cube i think sorry if its wrong