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babunello [35]
3 years ago
15

Solve the equations for all values of x by completing the square x^2+62=-16x

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
4 0

Answer:

x =  \sqrt{2} - 8\\x =  -\sqrt{2} - 8

Step-by-step explanation:

To complete the square, we first have to get our equation into ax^2 + bx = c form.

First we add 16x to both sides:

x^2 + 16x + 62 = 0

And now we subtract 62 from both sides.

x^2 + 16x = -62

We now have to add (\frac{b}{2})^2 to both sides of the equation. b is 16, so this value becomes (16\div2)^2 = 8^2 = 64.

x^2 + 16x + 64 = -62+64

We can now write the left side of the equation as a perfect square. We know that x+8 will be the solution because 8\cdot8=64 and 8+8=16.

(x+8)^2 = -62 + 64

We can now take the square root of both sides.

x+8 = \sqrt{-62+64}\\\\ x+8 = \pm \sqrt{2}

We can now isolate x on one side by subtracting 8 from both sides.

x = \pm\sqrt{2} - 8

So our solutions are

x =  \sqrt{2} - 8\\x =  -\sqrt{2} - 8

Hope this helped!

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