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Advocard [28]
2 years ago
8

Calculate the volume of 42.0g of tin (density 7.29g/ml)

Chemistry
1 answer:
Aleksandr-060686 [28]2 years ago
5 0

Answer:

try to calcutlae on paper

Explanation:

try to calculate on paper

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The true absorbance for a 1.0 x 10 −5 M solution is 0.7526. If the percentage stray light for a spectrophotometer is 0.56%, calc
Korvikt [17]

Answer:

The percentage deviation is  \Delta M = 1.87%

Explanation:

From the question we are told that  

     The concentration is of the solution is C = 1.0*10^{-5} M

     The true absorbance A = 0.7526

      The percentage of transmittance due to stray light z = 0.56% =\frac{0.56}{100}  = 0.0056

Generally Absorbance is mathematically represented as

           A = -log T

Where T is  the percentage of true transmittance

    Substituting value  

          0.7526 = - log T

              T = 10^{-0.7526}

                  = 0.177

                  = 17.7%

The Apparent absorbance is mathematically represented

           A_p = -log (T +z)

Substituting values

           A_p = -log(0.177 + 0.0056)

                = -log(0.1826)

               = 0.7385

The percentage by which apparent absorbance deviates from known absorbance is mathematically evaluated as

       \Delta A = \frac{A -A_p}{A} * \frac{100}{1}

              = \frac{0.7526 - 0.7385}{0.7526} * \frac{100}{1}

             \Delta A = 1.87%  

Since Absorbance varies directly with concentration the percentage deviation of the apparent concentration from know concentration  is

              \Delta M = 1.87%

           

6 0
3 years ago
1s22s22p63s23p64s23d104p65s24d9 what is this element
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Answer:

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Non-ionic strotium

Explanation:

4 0
3 years ago
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Explanation:

3 0
2 years ago
7. Which 2 structures, in the digestive system, reabsorb water into the body? _____________________ and ______________________
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7. Large Intestine and chemical digestion
8.stomach
9.capillaries
4.neurons

hopefully this is correct
3 0
3 years ago
How many moles of H atoms are in 15.2 grams of pure ice?
nikitadnepr [17]

The number of moles of H atoms in 15.2 grams of pure ice is 0.850 moles

The number of moles of O atoms in 15.2 grams of pure ice is 13.50 moles

<h3>What is an atom?</h3>

An atom is a smallest indivisible particle of a chemical element that is capable of independent existence.

  • Pure ice contains the H2O molecules and the molar mass of H2O is 18.02 g/mol

Using the relation:

  • number of moles = mass/molar mass

The number of moles of H2O = 15.2 grams/18.02 g/mol

number of moles of H2O = 0.8435 moles

If the atomic mass of H and O are as follow:

  • the atomic mass of H atom is = 1.00784 g/mol
  • the atomic mass of O atom is = 15.999 g/mol

Then:

the number of H atoms in 15.2 grams of pure ice = mass of H atom × molar mass of H2O.

the number of H atoms = 0.8435 mol × 1.00784 g/mol

the number of H atoms = 0.850 moles

the number of O atoms in 15.2 grams of pure ice = 0.8435 mol × 15.999 g/mol

the number of O atoms = 13.50 moles

Learn more about atoms here:

brainly.com/question/25832904

6 0
2 years ago
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