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Lapatulllka [165]
3 years ago
11

Calculate the standard cell potential at 25 ∘c for the reaction x(s)+2y+(aq)→x2+(aq)+2y(s) where δh∘ = -793 kj and δs∘ = -319 j/

k . express your answer to three significant figures and include the appropriate
Chemistry
1 answer:
QveST [7]3 years ago
5 0
First we will calculate free energy change:
ΔG₀ = ΔH₀ - (T * ΔS₀)
        = - 793 kJ - (298 * - 0.319 kJ/K) = - 698 kJ
We know the relation between free energy change and cell potential is:
ΔG₀ = - n F E⁰ where
F = Faraday's constant = 96485 C/mol
n = 2 (given by equation that the electrons involved is 2)
ΔG₀ = - 2 x 96485 x E⁰
- 698 kJ = - 2 x 96485 x E⁰
E⁰ = (698 x 1000) / (2 x 96485) = 3.62 volts   
 
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3 years ago
Write one common thing between condensation and hydrolysis ?​
serious [3.7K]

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8 0
2 years ago
Please help me out i will give you brainlist. 0.500 is wrong
Alik [6]
<h3>Answer:  b) 0.250 mol</h3>

============================================

Work Shown:

Using the periodic table, we see that

  • 1 mole of carbon = 12 grams
  • 1 mole of oxygen = 16 grams

These are approximations and these values are often found underneath the atomic symbol. For example, the atomic weight listed under carbon is roughly 12.011 grams. I'm rounding to 2 sig figs in those numbers listed above.

So 1 mole of CO2 is approximately 12+2*16 = 44 grams. The 2 is there since we have 2 oxygens attached to the carbon atom.

-------------------

Since 1 mole of CO2 is 44 grams, we can use that to convert from grams to moles.

11.0 grams of CO2 = (11.0 grams)*(1 mol/44 g) = (11.0/44) mol = 0.250 mol of CO2

In short,

11.0 grams of CO2 = 0.250 mol of CO2

This is approximate.

We don't need to use any of the information in the table.

3 0
3 years ago
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Calculate the mass (in g) of 2.1 x 1024 atoms of W.
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Atomic mass W = 183.84 u.m.a

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2.1x10²⁴ x 183.84 / 6.02x10²⁴ =

3.860x10²⁶ / 6.02x10²⁴ = 641.30 g

hope this helps!
4 0
3 years ago
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