First we will calculate free energy change: ΔG₀ = ΔH₀ - (T * ΔS₀) = - 793 kJ - (298 * - 0.319 kJ/K) = - 698 kJ We know the relation between free energy change and cell potential is: ΔG₀ = - n F E⁰ where F = Faraday's constant = 96485 C/mol n = 2 (given by equation that the electrons involved is 2) ΔG₀ = - 2 x 96485 x E⁰ - 698 kJ = - 2 x 96485 x E⁰ E⁰ = (698 x 1000) / (2 x 96485) = 3.62 volts