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Hoochie [10]
2 years ago
12

How many moles of calcium chloride would react with 5. 99 moles of aluminum oxide?

Chemistry
1 answer:
slega [8]2 years ago
6 0

There are 17.97 moles of calcium chloride would react with 5. 99 moles of aluminum oxide .

The balanced chemical equation between  reaction between calcium chloride and aluminum oxide is given as,

3CaCl_{2} (aq)+Al_{2} O_{3} (s) → 3CaO_{2} (s)+2Al Cl_{3} (aq)

The molar ratio of above reaction is  3:1

It means 3 moles of calcium chloride is require to react one mole of aluminum oxide.

The number of moles of calcium chloride requires to react with  5. 99 moles of  aluminum oxide  = 3 × 5. 99 = 17.97 moles

The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .

learn more about calcium chloride

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What is the pH of a 0.28 M solution of ascorbic acid
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Hey there!

Values Ka1 and Ka2 :

Ka1 => 8.0*10⁻⁵

Ka2 => 1.6*10⁻¹²

H2A + H2O -------> H3O⁺  + HA⁻

 Ka2 is very less so I am not considering that dissociation.

Now Ka = 8.0*10⁻⁵ = [H3O⁺] [HA⁻] / [H2A]

lets concentration of H3O⁺  = X then above equation will be

8.0*10−5 = [x] [x] / [0.28 -x

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solve the quardratic equation

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3 0
3 years ago
The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, re
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<u>Answer:</u> The temperature of the system will be 1622 K

<u>Explanation:</u>

The equation relating the pre-exponential factor and activation energy follows:

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where,

D = diffusion coefficient = 2.7\times 10^{-14}m^2/s

D_o = pre-exponential constant = 1.7\times 10^{-5}m^2/s

E_a = activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

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In adding the measurements 11.074 m, 18.2m, and 16.943 m, what should be the number of scientific figures in the result
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