Hey there, the answer is C.
After multiplying, you will get .37278. However, it's asking you to consider the significant figure of 3 so you'll have to round it to .373. C has that only option
Answer:

t = 2.2450
d. 0.264
Step-by-step explanation:
The null hypothesis is:

Alternative hypothesis;

The pooled variance t-Test would have been determined if the population variance are the same.



The t-test statistics can be computed as:



t = 2.2450
Degree of freedom 
df = (8-1)+(8-1)
df = 7 + 7
df = 14
At df = 14 and ∝ = 0.05;

Decision Rule: To reject the null hypothesis if the t-test is greater than the critical value.
Conclusion: We reject
and there is sufficient evidence to conclude that the test scores for contact address s less than Noncontact athletes.
To calculate r²
The percentage of the variance is;




Answer:
3+c < -29 or c+3 < -29 because of communitive property
Step-by-step explanation:
First, the sum means addition, you could write 3+c or c+3 because addition is communitive property.
Then the sum is less than -29 so we need to use the less than symbol which is this symbol: <
Now write the inequality! 3+c < -29
The expression (x^22) (x^7)^3 is equivalent to x^p what is the value of p
A) Let x = number of presale tickets
<span>y = number of day of show tickets </span>
<span>x + y =< 800 </span>
<span>6x + 9y >= 5000 </span>
<span>b) 6x + 9y >=5000 </span>
<span>6(440) + 9y >=5000 </span>
<span>y >= 262.2 </span>
<span>263 tickets </span>
<span>440 advance purchase tickets added to 263 day of show tickets is 703 tickets, which is below the 800 ticket maximum.</span>