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scoray [572]
3 years ago
10

What is the LCD of 1/6 and 3/10

Mathematics
1 answer:
Marta_Voda [28]3 years ago
6 0
The LCD is 30.

Think of it this way.  You and I are on an assembly line checking i-pads.  Your job is to quality check every 6th one and my job is to check every 10th one.
Here are the ones you will check:

6, 12, 18, 24, 30 and so on
Here are the ones I will check
10, 20 30 and so on.

Notice the first one we both check?  #30 - that is the LCD of 6 and 10
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Step-by-step explanation:

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The difference between a number and four is multiplied by negative five. The result is twenty. What is the number?
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Why the following triangles are congruent!
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Because the sides BO and MA are marked with one line through the middle, which means those sides are congruent, angle A and Angle O are marked with one line, the angles are congruent, and angles W and N are marked with two lines, which means they are congruent. Therefore the triangles are congruent

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3 years ago
Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the
sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let y(t) be the depth of water in the barrel at time t,  where y is measured in inches and t in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

                                                 \frac{dy}{dt}=-k\sqrt{y}

where k is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by \frac{1}{\sqrt{y}}

\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k

Multiply by dt

\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt

Take integral

\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt

Integrate

2\sqrt{y}=-kt+C

Isolate y

y(t)=(\frac{C}{2} -\frac{k}{2}t)^2

We know that the water level starts at 36, this means y(0)=36. We use this information to find the value of C.

36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12

y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2

At t = 1, y = 34

34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}

So our formula for the depth of water in the barrel is

y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\

To find the time, t, at which all the water leaks out of the barrel, we solve the equation

\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0
3 years ago
What is the domain of this exponential function? y=2x
trasher [3.6K]

Answer:

x∈R

Step-by-step explanation:

y=2^{x}

2>0

The domain is all real numbers.

x∈R

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