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3 years ago

Which of the following statements about infrared telescopes is NOT true?

Physics

1 answer:

nignag [31]3 years ago

4 0

Answer:

a. They are typically operated at lower temperatures.

a. They are typically operated at lower temperatures.b. They are especially helpful for viewing cool or obscured astronomical objects.

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A 100-meter sprint is a race using only the straight side of a racetrack. A 400-meter sprint is a race that makes one complete l

Shalnov [3]

Speed uses distance and velocity uses displacement in its calculation.

For 100 m race, distance = displacement. Hence speed = velocity

For 400m race, distance ≠ displacement. distance = 400m whereas displacement = 0m. Hence speed ≠ velocity

3 0

3 years ago

Read 2 more answers

Point charges of 21.0 μC and 47.0 μC are placed 0.500 m apart. (a) At what point (in m) along the line connecting them is the el

rewona [7]

Answer:

a) x = 0.200 m

b)E = 3.84*10^{-4} N/C

Explanation:

$q_1 = 21.0\mu C$

$q_1 = 47.0\mu C$

DISTANCE BETWEEN BOTH POINT CHARGE = 0.5 m

by relation for electric field we have following relation

$E = \frac{kq}{x}^2$

according to question E = 0

FROM FIGURE

x is the distance from left point charge where electric field is zero

$\frac{k21}{x}^2 = \frac{k47}{0.5-x}^2$

solving for x we get

$\frac{0.5}{x} = 1+ \sqrt{\frac{47}{21}}$

x = 0.200 m

b)electric field at half way mean x =0.25

$E =\frac{k*21*10^{-6}}{0.25^2} -\frac{k*47*10^{-6}}{0.25^2}$

E = 3.84*10^{-4} N/C

6 0

3 years ago

Read 2 more answers

An open-topped freight car with mass 24,000 kg is coasting without friction along a level track. It is raining very hard, and th

skelet666 [1.2K]

Answer:

(a) v = 3..6 m/s

(b) The rain falling downward has been able to affect the horizontal motion of the car by reducing it's velocity from 4 m/s to 3.6 m/s.

Explanation:

from the question we have the following:

mass of the car (Mc) = 24,000 kg

initial velocity of the car (u) = 4 m/s

mass of water (Mw) = 3000 kg

final velocity of the car (v) = ?

(a) we can calculate the final momentum of the car by applying the conservation of momentum where

initial momentum = final momentum

Mc x U = (Mc + Mw) x V

24000 x 4 = (24000 + 3000) x v

96,000 = 27000v

v =3.6 m/s

(b) The rain falling downward has been able to affect the horizontal motion of the car by reducing it's velocity from 4 m/s to 3.6 m/s.

7 0

3 years ago

Rocket engineers use newton's third law during launch. identify the action force.

rosijanka [135]

The answer is A. Newton's third law of motion states that for every action, there is an equal and opposite reaction. A rocket exerts a large force on the gas that is in the rocket chamber (action). The gas thus exerts a large reaction force forward on the rocket (reaction). The large reaction force is called thrust.

6 0

3 years ago

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A wave is described by y=0.0200 sin (kx - ωt) , where , ω = 3.62 rad/s, x and y are in meters, and t is in seconds.(b) the wavel

BartSMP [9]

For a wave is described by y=0.0200 sin (kx - ωt) , where , ω = 3.62 rad/s, x and y are in meters, and t is in seconds, the wavelength = 2.978

<h3>How to solve for the wavelength</h3>

What is wave speed?

This is used to refer to the speed at which a wave is moving. It is the product of frequency and wave number

Given data

y=0.0200 sin (kx - ωt)

ω = 3.62 rad/s

y are in meters

t is in seconds

k = 2.11 rad/m

k = wavenumber = 2 * pi / wavelength

wavelength = 2 * pi / wavenumber

wavelength = 2 * pi / 2.11

wavelength = 2.978