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Korolek [52]
3 years ago
9

Calculate using coulombs: an object has 6 protons and 8 electrons. Calculate the magnitude of the charge of the objects. Thank y

ou.
Physics
1 answer:
SVEN [57.7K]3 years ago
8 0

Answer:

-3.2 ×1.6 ×10^-19C

Explanation:

Number of proton = 6

Number of electron = 8

To determine the quantity of the charge, we would first find the difference between the number of

protons and electrons. Then multiply the difference by charge 1.6 x 10 -19 C to determine the charge on the object.

Difference between proton and electron is elementary charge

Elementary charge = proton - electron

= 6 - 8

Elementary charge = -2e

Recall, charge (q) = 1.6 ×10^-19C

1e = 1.6 ×10^-19C

Magnitude of the charge of object = -2× (1.6 ×10^-19C)

Magnitude of the charge of object = -3.2 ×1.6 ×10^-19C

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An action of push or pull on an object is force. The two bodies interact with each other. Newton's third law of motion states that every action has equal and opposite reaction. This means that if an object A exerts F amount of force on another object B, object B would also exert the same amount of force on A. when a person driving at speed 130 miles per hour hits wall, the wall would also apply an equal force on car and that would cause the damage to it.  

8 0
3 years ago
Read 2 more answers
An object is formed by attaching a uniform, thin rod with a mass of mr = 6.9 kg and length L = 4.88 m to a uniform sphere with m
Bumek [7]

Answer:

a)  total moment of inertia is 1359.05 kg m^2

b) angular acceleratio is 0.854rad/sec^2

Explanation:

Given data:

m1=6.9 kg

L=4.88 m

m2=34.5 kg

R=1.22 m

we klnow that moment of inertia for rod is given as

J1=(1/12) ×m×L^2

J1 = (1/12) \times 6.9 \times 4.88^2 = 13.693 kg m^2

moment of inertia for sphere is given as

J1=(2/5) ×m×r^2

J1 = (2/5) \times 34.5 \times 1.22^2 = 20.539 kg m^2

As object rotates around free end of rod then for sphere the axis around what it rotates is at a distance of d2=L+R

For rod distance is  d1=0.5*L

By Steiner theorem

for the rod we get J_1'=J_1 + m_1\times d_1^2

J_1' = 13.693 + 2.44^2\times 6.9 = 54.77 kg m^2

for the sphere we get J_2' = J_2 + m_2\times d_2^2

J2' = 20.539 + 34.5\times 6.1^2 = 1304.28 kg^m2

And the total moment of inertia for the first case is

J_{t1} = J_1'+J_2' = 54.77 + 1304.28 = 1359.05kg.m^2

b) F=476 N

The torque for system is given as

M = F\times d\times sin(a)

where a is angle between Force and distance d

and where d represent distance from rotating axis.

In this case a = 90 degree  

M = F\times L/2

M=476*2.44 = 1161.44 Nm

The acceleration is calculated as

a_1 = \frac{M}{J_{t1}}

      = \frac{1161.44}{1359.05}

      = 0.854 rad/sec^2

4 0
3 years ago
2. is a variable that gives location relative to an origi
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Where is the rest of the sentence?
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3 years ago
The brightest, hottest, and most massive stars are the brilliant blue stars designated as spectral class O. If a class O star wi
aksik [14]

Answer:

2.77 * 10^5 m/s

Explanation:

Let us recall that kinetic energy is given by 1/2 mv^2

Where;

m = mass of the body

v = velocity of the body

In this case,

m = 3.38 * 10^31 kg

KE= 1.30 * 10^42 J

KE = 1/2 mv^2

v = √2KE/m

v = √2 * 1.30 * 10^42/3.38 * 10^31

v = √7.69 * 10^10

v = 2.77 * 10^5 m/s

4 0
3 years ago
The inductive reactance of the circuit is exactly twice the resistance: XL=2R. Adjust the phasor that represents the voltage acr
SVETLANKA909090 [29]

Answer:

∅=63.43^{0}

Explanation:

z=impedance

x_{l}=2R

R=R

The resultant of the resistances in the circuit is called impedance

x_{l} is inductive reactance of the circuit

R is the resistance of the resistor

z=\sqrt{xl^{2}+R^2 }

z=\sqrt{2R^{2}+R^2 }

Z=\sqrt{5R^2}

Z=R\sqrt{5}ohms

tan∅=2R/R

tan∅=2

∅=Tan^-1(2)

∅=63.43^{0}

phase angle is ∅=63.43^{0}

3 0
3 years ago
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