Answer:
Explanation:
The equation for Power is
P = Work/time to do work and the equation for work is
Work = FΔx
We first need to find the amount of work done, then we can find the power it took to do that work.
W = 2000(9.8)(28) so
W = 550,000 N*m
Now we fill that into the power equation:
gives us
P = 18000 Watts. But we need kW, so we divide by 1000 to get
P = 18 kW of power.
Answer:
the acceleration during the collision is: - 5
Explanation:
Using the formula:

we get:

A single fixed pulley can be used to raise or lower lightweight objects.
Option b
<u>Explanation:</u>
A pulley is a simple machine tool which is used to make lifting or lowering tasks easy. A single fixed pulley is a system involving only one pulley fixed on a constant rigid support with a rope wrapped around the wheel. Such a system can be used only to change the direction of applied force in raising or lowering small, lightweight objects which need minimal work force.
A single fixed pulley system helps only in redirecting the applied force direction by using a rope and wheel assembly. The work done in such a case remains the same and hence it is not preferred to use it in lifting heavy objects. Neither is the required force reduced in case of a single fixed pulley system. A movable pulley helps in achieving (A) and (C).
Answer:
the force acting on the car is 3600 N
Explanation:
The computation of the force acting on the car is shown below:
As we know that
Force = mass × acceleration
= 1200 kg × 3.0 ms/^2
= 3600 N
hence, the force acting on the car is 3600 N
Answer:
The length of the simple pendulum is 2.4 meters.
Explanation:
Time period of simple pendulum is given by :

L is the length of pendulum
The time period of the rope is given by :

L' is the length of the rod, L' = 3.6 m
It is given that, the rod have the same period as a simple pendulum and we need to find the length of simple pendulum i.e.

On solving the above equation as :

L = 2.4 m
So, the length of the thin rod that is hung vertically from one end and set into small amplitude oscillation 2.4 meters. Hence, this is the required solution.