Should athletes be benched if their grades are too low, or should they be allowed to play anyway?

Earth and other planets closest to the sun are mostly made of ______?

weqwewe [10]

The answer is a rocks

5 0

3 years ago

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A gas bottle contains 7.86×10^23 Oxygen molecules at a temperature of 327.0 K.

castortr0y [4]

Answer:

1. E=5320.3J

2. E= 1773.45J

3. E=6.76*10^{-21}J

4. E=2.25*10^{-21}J

Explanation:

1. the thermal energy is given by the formula

$E_T=\frac{3}{2}NK_BT=\frac{3}{2}(7.86*10^{23})(1.38*10^{-23}\frac{J}{K})(327.0K)=5320.3J$

where KB is the Boltzmann's constant, T is the temperature and N is the number of molecules in the system.

2. Each degree of freedom contains one half of the total energy. Hence, the energy for one degree of freedom is

$E_1=\frac{1}{2}NK_BT=1773.45J$

3.

$E=\frac{3}{2}K_BT=6.76*10^{-21}J$

4.

$E=\frac{1}{2}K_BT=2.25*10^{-21}J$

Hope this helps!!

6 0

3 years ago

Audible wavelengths. the range of audible frequencies is from about 20.0 hz to 2.00×104 hz . what is range of the wavelengths of

BabaBlast [244]

Given:
f1 = 20 Hz
f2 = 20000 Hz
speed of sound at 20 degrees celcius = 343 m/s

Solution:

for f1 = 20 Hz,

Using the equation:

lambda = speed of sound / f1 = 343 / 20 = 17.15 m

For f2:

lambda = speed of sound / f2 = 343 / 20000 = 0.01775 m

Therefore the wavelength range of audible sound in air would be 17.15 m to 0.01775 m.

6 0

3 years ago

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Can anyone help me with this

Murrr4er [49]

Answer:

event s

Explanation:

the cow gets oxygen from the tree and proceeds to respirate.

8 0

3 years ago

Jack and Jill are on two different floors of their high rise office building and looking out of their respective windows. Jack s

Maru [420]

Answer:

a) speed when Jack sees the pot : 12.92 meters per second

b) height difference 163.115 meters

Explanation:

First to calculate te initial speed we use the acceleration formula:

a= v1-v0/t

Acceleration being gravity's acceleration (9.8 m/s^2)

v1 being the speed when Jill sees the pot

v0 when Jack sees it

and t the time between

Solving for v0 it would be

v1 - a*t = v0

replacing

$58 m/s - 9.8 m/s^2 *4.6 s = v0 = 12.92 m/s$

For the second question we use the position formula setting y0 and t0 as the position and time when jack sees the pot. (and setting the positive axis downward I.E. one meter below jack would be 1m not -1m)

The formula is

$y0 + v0*t + 1/2 g *t^2 = yt$

replacing

$0m + 12.92m/s* 4.6 s + 1/2 * 9.8 m/s^2 * (4.6 s)^2 = 163.115 m$

5 0

3 years ago