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Marrrta [24]
3 years ago
8

Forces always come in pairs — so each ______ has a reaction

Physics
1 answer:
Wittaler [7]3 years ago
7 0
Every action has an equal opposite reaction
You might be interested in
a) One of the moons of Jupiter, named Io, has an orbital radius of 4.22 108 m and a period of 1.77 days. Assuming the orbit is c
hoa [83]

Answer:

According to Kepler's 3rd law.

It states that the orbital period, T is related to the distance, r as:

T² =  4 π²r³ /G  M

where G is the universal gravitational constant  =  6.673 × 10⁻¹¹ Nm²/kg²

Rearranging for M should give Jupiter's mass.

M =   4 π²r³/GT²

T= 1.77 days × 24 h/day × 60 min/h × 60 s/min = 1.53 × 10⁵ s

r = 4.22x10⁸ m

M = 4π² ((4.22 × 10⁸ m)³/(6.673 × 10⁻¹¹ Nm²/kg² x (1.53 × 10⁵ s)²)

M = 1.90 × 10²⁷kg

The mass of Jupiter is 1.90 × 10²⁷kg.

1.90 × 10²⁷kg

T= 7.16 days × 24 h/day × 60 min/h × 60 s/min = 6.19 × 10⁵s

r = 1.07x10⁹ m

M = 4π² ((1.07 × 10⁹ m)³/(6.673 × 10⁻¹¹ Nm²/kg² x (6.19 × 10⁵ s)²)

M = 1.90 × 10¹⁷kg

The mass of Jupiter is 1.90 × 10¹⁷kg.

THE RESULTS TO PART A and B ARE NOT CONSISTENT. The reason is because of the difference in radius of each satellites from Jupiter. i.e the farther away the moons, the smaller they become in space and the more the number of days to complete an orbit.

8 0
3 years ago
During a hard sneeze, your eyes might shut for 0.32 s. If you are driving a car at 76 km/h during such a sneeze, how far does th
garik1379 [7]

Answer:

Distance, d = 6.75 meters

Explanation:

Given that,

Time taken by the eyes to shut during a hard sneeze, t = 0.32 s

Speed of the car, v = 76 km/h = 21.11 m/s

We need to find the distance covered by the car during this time. The product of speed and the time taken by the car is called the distance covered by the it. Mathematically,

d=v\times t

d=21.11\times 0.32

d = 6.75 meters

So, the car will cover 6.75 meters during that time. Hence, this is the required solution.

8 0
3 years ago
Define simple machine with any two examples​
ryzh [129]

Answer:

They are the simplest mechanisms known that can use leverage (or mechanical advantage) to increase force. The simple machines are the inclined plane, lever, wedge, wheel and axle, pulley, and screw. simple machines.

6 0
2 years ago
Read 2 more answers
4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718
Dmitry_Shevchenko [17]

Question

4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid

Hold on, our servers are swamped. Wait for your answer to fully load.

Answer:

Explanation:4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid

8 0
2 years ago
A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.060 m/s and acceleration -0.3
shusha [124]

Answer:

a

  x_2 = -2.3356

b

 v = -1.384 \ m/s

Explanation:

From the question we are told that

  The initial position of the particle is  x_1 = 0.180 \ m

  The initial  velocity of the particle is  u = 0.060  \  m/s

  The acceleration is   a = -0.380 \  m/s^2

   The time duration is  t = 3.80  \ s

Generally from kinematic equation

    v = u + at

=>  v = 0.060 + (-0.380 * 3.80)

=>  v = -1.384 \ m/s

Generally from kinematic equation

   v^2 = u^2 + 2as

Here s is the distance covered by the particle, so

   (-1.384)^2 = (0.060)^2 + 2(-0.380)* s

=>  s = -2.5156 \ m

Generally the final position of the particle is  

    x_2 = x_1 + s

=>   x_2 = 0.180 + (-2.5156)

=>   x_2 = -2.3356

6 0
3 years ago
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