Answer:
1143 N at 1.59 m from the left end
Explanation:
For the system to produce equilibrium, the total force and moment must be 0. Since the total weight downward is
481 + 381 + 281 = 1143 N
Therefore the magnitude of the force acting upward to balance this system must be the same of 1143 N
That alone is not enough, we also need the position of the force for the total moment to be 0.
Let x be the length from the this upward force to the left side. And let the left point be the point of reference for moment arm:
481 * 3.32/2 + 381 * 0.8798 + 281*(3.32 - 0.8798) - 1143*x = 0
x = (481*1.66 + 381 * 0.8798 + 281*2.4402)/1143 = 1.59m
Answer:
volume of the bubble just before it reaches the surface is 5.71 cm³
Explanation:
given data
depth h = 36 m
volume v2 = 1.22 cm³ = 1.22 × 
m³
temperature bottom t2 = 5.9°C = 278.9 K
temperature top t1 = 16.0°C = 289 K
to find out
what is the volume of the bubble just before it reaches the surface
solution
we know at top atmospheric pressure is about P1 = 
Pa
so pressure at bottom P2 = pressure at top + ρ×g×h
here ρ is density and h is height and g is 9.8 m/s²
so
pressure at bottom P2 = + 1000 × 9.8 ×36
pressure at bottom P2 =4.52 × Pa
so from gas law
here p is pressure and v is volume and t is temperature
so put here value and find v1
V1 = 5.71 cm³
volume of the bubble just before it reaches the surface is 5.71 cm³
Answer:
Half life of S = 3.76secs
Explanation:
The concept of half life in radioactivity is applied. Half life is the time taken for a radioactive material to decay to half of its initial size.
For part 1 - How much signal will be degraded in 1secs = 1/3.9 = 0.2564
for part 2 - How much signal will be degraded in 1secs = 1/104 = 0.009615
Simply say = 1/3.9 + 1/104 = 0.266015
So both part 1 and part 2 took 1/0.266015 = 3.76secs is the half life of S when both pathways are active
The resolution of a microscope is the distance with the shortest measurement between two different points given a specimen with the premise that it can still be seen clearly or distinguished by the one looking through the microscope. It can be calculate from the ratio of the wavelength of the light and twice the numerical aperture or the refractive index of the lens. Most of the microscopes have a numerical aperture ranging from 1.2 to 1.4. Resolution and the numerical aperture are indirectly proportional so that as the aperture increases the resolution would decrease. We calculate as follows:
<span>Resolution = wavelength / ((2) (numerical aperture))
Resolution = 500 nm / (2 ) ( 1.25) = 200 nm = 0.2 um</span>
