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balandron [24]
2 years ago
15

What is gravitonal force

Physics
1 answer:
zhuklara [117]2 years ago
8 0

Answer:

its something that hold the air for forceing liy by the exgen

Explanation:

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A baseball player leads off the game and hits a long home run. The ball leaves the bat at an angle of 70.0 from the horizontal w
professor190 [17]

Answer: 211.059 m

Explanation:

We have the following data:

\theta=70\° The angle at which the ball leaves the bat

V_{o}=55 m/s The initial velocity of the ball

g=-9.8 m/s^{2} The acceleration due gravity

We need to find how far (horizontally) the ball travels in the air: x

Firstly we need to know this velocity has two components:

<u>Horizontally:</u>

V_{ox}=V_{o}cos \theta (1)

V_{ox}=55 m/s cos(70\°)=18.811 m/s (2)

<u>Vertically:</u>

V_{oy}=V_{o}sin \theta (3)

V_{oy}=55 m/s sin(70\°)=51.683 m/s (4)

On the other hand, when we talk about parabolic movement (as in this situation) the ball reaches its maximum height just in the middle of this parabola, when V=0 and the time t is half the time it takes the complete parabolic path.

So, if we use the following equation, we will find t:

V=V_{o}+gt=0 (5)

Isolating t:

t=\frac{-V_{o}}{g} (6)

t=\frac{-55 m/s}{-9.8 m/s^{2}} (7)

t=5.61 s (8)

Now that we have the time it takes to the ball to travel half of is path, we can find the total time T it takes the complete parabolic path, which is twice t:

T=2t=2(5.61 s)=11.22 s (9)

With this result in mind, we can finally calculate how far the ball travels in the air:

x=V_{ox}T (10)

Substituting (2) and (9) in (10):

x=(18.811 m/s)(11.22 s) (11)

Finally:

x=211.059 m

8 0
3 years ago
which do you think would be warmer on a winter day when there is no wind a thick forest or a grassy field? explain your answer
Tju [1.3M]
I think it would be warmer in a grassy field with no wind on a winter day because you'll have sunlight hitting you. However, if you were in a thick forest, all sunlight would be blocked and you would have no warmth from the sun. 
4 0
3 years ago
Read 2 more answers
The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.40 the weight of the object
Ann [662]

The frictional force of an object is the product of the normal force and coefficient of kinetic friction. Here the frictional force acting on the object  is 16.4 N.

<h3>What is frictional force?</h3>

Frictional force is a kind of force acting on a body to resist it from motion. Thus, the direction of the force will be in negative with the magnitude. Frictional force is the product of coefficient of friction and the normal force.

The normal  force acting on the object of mass 4.2 Kg is N = mg

N = 4.2 Kg × 9.8 m/s² = 41.16 N

Frictional force = ц N

                         = 0.40 × 41.16 N

                         = 16.4 N.

Therefore, the frictional force acting between the surface of the object and the floor is 16.4 N

To find more on frictional force, refer here:

brainly.com/question/1714663

#SPJ1

Your question is incomplete. But your complete question probably was:

The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.40 the weight of the object is 4.2 kg. What is the frictional force of the object?

3 0
1 year ago
Seattle, Washington and Bismarck, North Dakota experience very different temperatures even though they are at the same latitude.
Likurg_2 [28]

Answer:

BELOW

Explanation:

Seattle (near water) would have hotter temperatures because it is by a large body of water. Unlike Bismarck which is surrounded by land. Bismarck would get hotter. Seattle would be affected the large body of water which heats more slowly than the continent warming.

8 0
2 years ago
Read 2 more answers
When one person shouts at a football game, the sound intensity level at the center of the field is 58.4 dB. When all the people
Tanzania [10]

Answer:

The number of people at game are approximately 22909

Explanation:

Given data

When one person shout \beta _{1}=58.4dB

When n number of person shout together \beta _{n}=102dB

The sound intensity level during one person shout is given by:

\beta _{1}=10log(\frac{I_{1}}{I_{o}} )\\58.4=10log(\frac{I_{1}}{I_{o}} )\\5.84=log(\frac{I_{1}}{I_{o}} )\\\frac{I_{1}}{I_{o}} =10^{5.84}\\I_{1}=10^{5.84}*I_{o}

The sound intensity level during n number of person shout is given by:

\beta _{n}=10log(\frac{I_{n}}{I_{o}} )\\102=10log(\frac{I_{n}}{I_{o}} )\\10.2=log(\frac{I_{n}}{I_{o}} )\\\frac{I_{n}}{I_{o}}=10^{10.2}\\I_{n}=10^{10.2}*I_{o}

Since each person generates same sound intensity and hence total number  of persons can be determined as

 =\frac{I_{n}}{I_{1}}\\ =\frac{10^{10.2}I_{o}}{10^{5.84}I_{o}} \\=22909

Hence

The number of people at game are approximately 22909

3 0
3 years ago
Read 2 more answers
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