I'll explain it simply for you
1st question
Of course you know phythagoras theorm
You even wrote it up there
It states that the sum of the square of the two sides of an equilateral triangle is equal to the square of the hypotenuse
![{a}^{2} + {b}^{2} = {c}^{2}](https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%7Bb%7D%5E%7B2%7D%20%20%20%3D%20%20%7Bc%7D%5E%7B2%7D%20)
Where C is the hypotenuse
*NOTE* :
HYPOTENUSE is the greatest side in a triangle!!
And that's where your mistake is!
So you should take the greatest side as C
So in Q3. 7, 24 and 26 are the given numbers
You'll make the smaller two numbers a and b and the greatest number C
Using the Formula you'll solve the left side first which is
![{a}^{2} + {b}^{2}](https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%7Bb%7D%5E%7B2%7D%20)
Then the right side which is
![{c}^{2}](https://tex.z-dn.net/?f=%20%7Bc%7D%5E%7B2%7D%20)
And if both are equal then it is a right triangle otherwise it isn't!
Let
a=7
b=24
c=26
a^2 + b^2
7^2 + 24^2
49 + 576 = 625
GREAT, Now the right side
26^2 = 676
Since they aren't equal it isn't a right angled triangle...
Then let
a=7.5
b=10
c=12.5
7.5^2 + 10^2
= 56.25 + 100
= 156.25
12.5^2 = 156.25
They are EQUAL
Therefore it is a right triangle too
Hopefully I helped
Answer:
no se
Step-by-step explanation:
pero muchas gracias
We know that the shorter side of the rectangle is 1/2 of the longer side (because it's a square folded in half). To meet this condition and to have a perimeter of 24cm, we may assume that the dimension of the rectangle are 8cm x 4cm.
Now if we unfold it, we'll get a square of 8cm x 8cm. To find the are we just need to find 8², which is <u>64 cm²</u>.
Answer:
I'm not a math whiz, but if I am not mistaken I believe you find the surface area of a full circle, take that answer and divide it by two since it is a half circle. Don't forget to show your work and pi is 3.14.
Hope I helped,
Adrian Velez
Step-by-step explanation: