Find the surface area of the regular hexagonal prism.

There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,

lys-0071 [83]

According to given information there are :

5 red balls

4 blue balls

6 yellow balls

10 green balls

<h3>1. what is the probability that the ball chosen is red ?</h3>

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$\qquad \sf \dashrightarrow \: p(red) = \dfrac{total \: red \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{25}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{1}{5}$

<h3>2. what is the probability that the ball chosen is blue ?</h3>

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{total \: blue \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{25}$

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{total \: yellow\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{25}$

<h3>4. what is the probability that the ball chosen is green ?</h3>

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{total \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{25}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{2}{5}$

<h3>5. what is the probability that the ball chosen is not green ?</h3>

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{total \: non \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{15}{25}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{3}{5}$

3 0

2 years ago

Graph of a line with the points (3, 2) and (3, –4) plotted.

Liono4ka [1.6K]

The correct equation is x=3 because there is no (Y) in the rise over run (y/x) meaning the starting point up and down the point on the (X)

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B6%7D%20%2B%20%20%5Cfrac%7B1%7D%7B8%7D%20" id="TexFormula1" title=" \frac{2

Viefleur [7K]

22/48 = 11/24

Answer : 11/24

3 0

3 years ago

What is 3/8 + 1/8?? Please help its for a test

Grace [21]

Answer:

1/2 is the answer

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If anyone knows the answer to these can u please help? thank you! :)

Dennis_Churaev [7]

Answers:

A) Ray QS or Ray QR
B) Line segment QS or SQ
C) Plane QSR
D) Line QS or RQ

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Explanation:

Part A)

When naming a ray, always start at the endpoint. This is the first letter and we'll start with point Q.

The second letter is the point that is on the ray where the ray aims at. We have two choices S and R as they are both on the same ray. That's why we can name this Ray QS and Ray QR.

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Part B)

A segment is named by its endpoints. The order of the endpoints doesn't matter so that's why segment QS is the same as segment SQ. To me, it seems more natural to read from left to right, so QS seems better fitting (again the order doesn't matter).

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Part C)

When forming a plane, you need 3 noncollinear points. The term "collinear" means the points all fall on the same line. So these three points cannot all fall on the same straight line. In other words, we must be able to form a triangle of some sort.

So that's how we get the name "Plane QSR". The order of the letters doesn't matter.

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Part D)

To name a line, we just need to pick two points from it. Any two will do. The order doesn't matter. So that's how we get Line QS and Line RQ as two aliases for this same line. It turns out that there are 6 different ways to name this line.

Line QR
Line QS
Line RQ
Line RS
Line SQ
Line SR

4 0

2 years ago