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Romashka-Z-Leto [24]
2 years ago
5

Using the average atomic masses given inside the front cover of this book, calculate the number of atoms present in each of the

following sample. a. 1.50 g of silver, Ag
b. 0.0015 mole of copper, Cu
C. 0.0015 g of copper, Cu
d. 2.00 kg of magnesium, Mg
e. 2.34 oz of calcium, Ca
f. 2.34 g of calcium, Ca
g. 2.34 moles of calcium, Ca
Chemistry
1 answer:
alexandr1967 [171]2 years ago
6 0

Answer:

c. 0.0015 g of coopet, cu

Explanation:

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<u>Answer:</u>

<em>20, 44, 62 </em>

<em></em>

<u>Explanation:</u>

To find the number of atoms of each element, we multiply coefficient and subscript  

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5 × 2 = 10, Cl atoms  

If there is a bracket in the chemical formula  

For example 3Ca_3 (P_1 O_4 )_2

we multiply coefficient × subscript × number outside the bracket to find the number of atoms  

(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9 , Ca atoms  

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3 × 4 × 2 = 24, O atoms are present.

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2C_{10} H_{22} (l)+31O_2 (g)\Rightarrow 20CO_2 (g)+22H_2 O(g)

Number of C atoms = 2 × 10 = 20

Number of H atoms = 2 × 22 = 44

Number of O atoms = 31 × 2 = 62

20, 44, 62  are the Answers.

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(divide)

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