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GaryK [48]
3 years ago
7

Un hidrocarburo tiene como composición en masa: C= 85.8% ; H= 14.2% . Como dato nos brindan que una molécula de este compuesto p

esa: LaTeX: 2.1x10^{-22}g2.1 x 10 − 22 g. Hallar la fórmula molecular. Datos: P.A (uma): C=12, H=1
Chemistry
1 answer:
OLga [1]3 years ago
8 0

Answer:

C_{9.042}H_{17.958}

Explanation:

(This exercise has been written in Spanish and for that reason explanation will be held in such language)

Por la definición del Número de Avogadro, un mol del compuesto contiene 6.022 \times 10^{23} moléculas. La masa de un mol se determina mediante regla de tres simple:

x = \frac{6.022\times 10^{23}\,molecules}{1\,molecule} \times (2.1\times 10^{-22}\,g)

x = 126.462\,g

Las participaciones másicas del carbono y el hidrógeno son, respectivamente:

m_{C} = 0.858\cdot (126.462\,g)

m_{C} = 108.504\,g

m_{H} = 126.462\,g - 108.504\,g

m_{H} = 17.958\,g

Ahora, el número de moles de cada elemento es calculado a continuación:

n_{C} = \frac{108.504\,g}{12\,\frac{g}{mol} }

n_{C} = 9.042\,mol

n_{H} = \frac{17.958\,g}{1\,\frac{g}{mol} }

n_{H} = 17.958\,mol

La fórmula molecular del hidrocarburo es:

C_{9.042}H_{17.958}

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