Answer: M'(2, - 5), L'(-2, -5), j'(-4, - 1)
Step-by-step explanation:
When we do a reflection over a given line, the distance between all the points (measured perpendicularly to the line) does not change.
The line is y = 1.
Notice that a reflection over a line y = a (for any real value a) only changes the value of the variable y.
Let's reflect the points:
J(-4, 3)
The distance between 3 and 1 is:
D = 3 - 1 = 2.
Then the new value of y must also be at a distance 2 of the line y = 1
1 - 2 = 1
The new point is:
j'(-4, - 1)
L(-2, 7)
The distance between 7 and 1 is:
7 - 1 = 6.
The new value of y will be:
1 - 6 = -5
The new point is:
L'(-2, -5)
M(2,7)
Same as above, the new point will be:
M'(2, - 5)
Step-by-step explanation:
Area of Square ABCD = 10m * 10m = 100m².
Answer:
1/2²m²
Step-by-step explanation:
She buys 2/8 more pound of granola than banana chips
The elimination method works by adding the two equations and eliminating one variable. Then you solve an equation in one variable. Finally, you use substitution or elimination again to find the other variable. Sometimes, by simply adding the equations, a variable is not eliminated. Then you need to multiply one or both equations by a factor to get a variable to be eliminated.
A)
2x - 4y = 8
x + 3y = -11
Adding the equations does not eliminate x or y.
Notice that in the first equation, every coefficient is even. We can divide both sides of the first equation by 2. Then the first term would be x. Instead, let's divide both sides of the first equation by -2. Then the x's will be eliminated.
-x + 2y = -4 <-- The first equation divided by -2
x + 3y = -11 <-- The original second equation. Now we add the equations.
----------------
5y = -15
y = -3
Now that we know y = -3, we substitute it into the first original equation and solve for x.
2x - 4y = 8
2x - 4(-3) = 8
2x + 12 = 8
2x = -4
x = -2
Answer: x = -2; y = -3
B)
We see that the x's will be eliminated by addition. Just add the equations.
-3x + 7y = 9
3x - 7y = 1
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0 + 0 = 10
0 = 10 <---- this is a false statement, so this system of equations has no solution.
