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Given:
Vertices of a square are A(-4,6), B(5,6) C(4,-2), and D(-5,-2).
To find:
The intersection of the diagonals of square ABCD.
Solution:
We know that diagonals of a square always bisect each other. It means intersection of the diagonals of square is the midpoint of diagonals.
In the square ABCD, AC and BD are two diagonals. So, intersection of the diagonals is the midpoint of both AC and BD.
We can find midpoint of either AC or BD because both will result the same.
Midpoint of A(-4,6) and C(4,-2) is
Therefore, the intersection of the diagonals of square ABCD is (0,2).
To find the area of a trapezoid, we use the following formula:
In this formula a represents the area and b1 and b2 each represent a base of the trapezoid.
So, we have got the following information
Filling in the formula gives us:
Finally we have to divide both sides by 15.
Therefore, the height of the trapezoid is 10 meters.
In this formula a represents the area and b1 and b2 each represent a base of the trapezoid.
So, we have got the following information
Filling in the formula gives us:
Finally we have to divide both sides by 15.
Therefore, the height of the trapezoid is 10 meters.