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Setler [38]
2 years ago
12

A farmer divides a rectangular piece of land with a perimeter of 140 yards into two triangular parts as shown in the diagram. If

the area of ABC is 600 square yards, what is the area of ACD? A. 880 square yards B. 740 square yards C. 600 square yards D. 460 square yards

Mathematics
2 answers:
Kazeer [188]2 years ago
8 0

Answer:

C

Step-by-step explanation:

Anton [14]2 years ago
6 0

Answer:

C. 600 square yards

Step-by-step explanation:

PLATO

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For his long distance phone service, Scott pays a $6 monthly fee plus 8 cents per minute. Last month, Scott's long distance bill
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\text{We need to find how many minutes Scott had in his phone service}\\\\\text{We know that he pays \$6 a month, 0.08 cents per minute, and was}\\\text{billed \$17.92 in total}\\\text{Turn this into an equation:}\\\\17.92 =0.08x+6\\\\\text{Solve for x:}\\\\17.92 =0.08x+6\\\\\text{Subtract 6 from both sides}\\\\11.92=0.08x\\\\\text{Divide by 0.08}\\\\x = 149\\\\\boxed{\text{Scott was billed for 149 minutes}}

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3 years ago
Khan Academy Order Rational Numbers<br><br> Please help, I will mark brainliest.
11111nata11111 [884]

Answer:

C= -1/5

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C= -3/7

Step-by-step explanation:

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3 years ago
What is the equation of the line 2-3y = 18 in slope-intercept form?
il63 [147K]
The person above me got that horrible wrong, do not put that.

You also wrote the question wrong, please be more careful when posting.

x-3y=18

Move x to the other side by subtracting it since it’s positive.

-3y = -x + 18

Divide the whole equation by -3 to find the value of just 1 y.

-3y/-3 = -x/-3 + 18/-3

y = 1/3x -6
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3 years ago
Help???!!??????!??!!???!????!??
svet-max [94.6K]
x_{vertex}= \frac{-2}{2 \cdot 3}=- \frac{2}{6}=  - \frac{1}{3} \\\\\\ &#10;y_{vertex}=3 \cdot \left(- \frac{1}{3} \right)^2+2 \cdot \left(- \frac{1}{3} \right)+1=3 \cdot\frac{1}{9} -  \frac{2}{3} +1=\frac{1}{3} -  \frac{2}{3} +1= \frac{2}{3}  \\  \\  \\ \boxed {\text {Answer:} \ \left(- \frac{1}{3};  \frac{2}{3} \right)}
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3 years ago
Any help with this greatly appreciated.
Anestetic [448]

Put the equation in standard linear form.

x'(t) + \dfrac{x(t)}{t + 5} = 5e^{5t}

Find the integrating factor.

\mu = \exp\left(\displaystyle \int \frac{dt}{t+5}\right) = e^{\ln|t+5|} = t+5

Multiply both sides by \mu.

(t+5) x'(t) + x(t) = 5(t+5)e^{5t}

Now the left side the derivative of a product,

\bigg((t+5) x(t)\bigg)' = 5(t+5)e^{5t}

Integrate both sides.

(t+5) x(t) = \displaystyle 5 \int (t+5) e^{5t} \, dt

On the right side, integrate by parts.

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