1. How many grams does 10 moles of Carbon weigh?

s344n2d4d5 [400]

It is true

a process by which the contents of a cell vacuole are released to the exterior through fusion of the vacuole membrane with the cell membrane.

6 0

3 years ago

Which of the following scenarios best illustrates the opponent-process theory of color vision?

Kitty [74]

Answer:

Kayla sees afterimages of opposing colors when she stares at a poster for a long time.

Explanation:

The "opponent-process theory" is a theory developed by Edward Hering. It states that three color pairs, which are opposing in nature, are linked by the cone receptors. These pairs are:

blue/yellow
red/green
black/white

This can be done when you stare at an afterimage patch for 30 seconds. Such as what Kayla is doing. Once the color stimuli is removed and she fixates her attention to a dot at the center of her field, she'll notice the colors being reversed. This means that if she sees the original color as "blue," she'll see it now as "yellow" and vice-versa.

Extended inspection of a color in a pair results to it being fatigued. This allows the non-fatigued color pair to be noticed.

So, this explains the answer.

6 0

3 years ago

A chemist wants to extract copper metal from copper chloride solution. The chemist places 0.25 grams of aluminum foil in a solut

mrs_skeptik [129]

Answer: The correct answer is about 0.20 grams of copper (II) is formed, and some aluminum is left in the reaction mixture.

Explanation:

To calculate the number of moles, we use the formula:

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of Aluminium:

Molar mass of aluminium = 27 g/mol

Given mass of aluminium = 0.25g

Putting values in above equation, we get:

$Moles=\frac{0.25g}{27g/mol}=0.00925mol$

Moles of Copper chloride:

Molar mass of copper chloride = 134.45 g/mol

Given mass of copper chloride= 0.40g

Putting values in above equation, we get:

$Moles=\frac{0.40g}{134.45g/mol}=0.00297mol$

For the given chemical equation:

$4Al(s)+3CuCl_2(aq.)\rightarrow 2Al_2Cl_3(aq.)++3Cu(s)$

By Stoichiometry,

3 moles of Copper chloride reacts with 4 moles of aluminium

So, 0.00297 moles of copper chloride will react with = $\frac{4}{3}\times 0.00297$ = 0.00396 moles of Aluminium.

As, the required moles of aluminium is less than the given moles of aluminium. Hence, it is considered as the excess reagent.

Copper chloride is the limiting reagent in the given chemical reaction because it limits the formation of products.

By Stoichiometry of the reaction:

3 moles of copper chloride produces 3 moles of copper metal.

So, 0.00297 moles of copper chloride will produce = $\frac{3}{3}\times 0.00297$ = 0.00297 moles of copper metal.

Now, to calculate the given mass of copper metal, we use the equation required to calculate moles:

Molar mass of copper = 63.5 g/mol

Putting values in that equation, we get:

$0.00297mol=\frac{\text{given mass}}{63.5g/mol}$

Given mas of copper metal = 0.188grams (approx 0.20grams)

For the given reaction, some of the aluminum is left behind because it is the excess reagent in the reaction.

Hence, the correct answer is about 0.20 grams of copper (II) is formed, and some aluminum is left in the reaction mixture.

6 0

3 years ago

Read 2 more answers

1- A sample of gas is in a 3.00 L contain at a pressure of 740.0 mmHg. What is the new pressure of the sample if the container's

inna [77]

Considering the Boyle's law, the new pressure of the sample is 1,776 mmHg.

<h3>What is Boyle's law</h3>

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.

Boyle's law states that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following will be true:

P1×V1=P2×V2

<h3>New pressure</h3>

In this case, you know:

P1= 740 mmHg
V1= 3 L
P2= ?
V2= 1.25 L

Replacing in Boyle's law:

740 mmHg× 3 L=P2× 1.25 L

Solving:

P2= (740 mmHg× 3 L) ÷ 1.25 L

P2= 1,776 mmHg

Finally, the new pressure of the sample is 1,776 mmHg.

Learn more about Boyle's law:

brainly.com/question/4147359

#SPJ1

7 0

2 years ago

Read 2 more answers

What were the expected results of Rutherford’s gold foil experiment, based on Thomson’s model of the atom? How did the real resu

forsale [732]

The expected results of the Rutherford's gold foil experiment were that the relative massive alpha particles (respect to electrons) could go through the gold foil without being deviated of their trajectory or only small deviations due to the uniformly distributed positive charge of the protons. The real results showed that some particles were significantly deviated of the trajectory (large deviation angles and even some particles bounced back to the source). This lead Rutherford to reject the plum pudding model and propose a new one. The new model proposed by Rutherford was that the atom consisted of a small and every dense nucleus (which contained the positive charge, protons) and a vast region, almost empty, but where the electrons were, surrounding the nucleus.

3 0

3 years ago

Read 2 more answers