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3 years ago

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What was the problem with Rutherford's model? a. It described a nucleus. c. It could not explain the chemical properties of elem

ents. b. It did not include electrons d. It described quantums.

1 answer:

schepotkina [342]3 years ago

7 0

<span>What was the problem with Rutherford's model?

</span>
<span> c. It could not explain the chemical properties of elements. </span>

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One mole of which of these compounds contains two moles of hydrogen atoms? f NaOH g H2S h CH4 j NH3

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G. H2S contains two hydrogen atoms

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3 years ago

What does the second law of thermodynamics say about entropy

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Answer:

The entropy and the systems surrounding it tend to increase.

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We can prove a theory to be correct by performing the right experiment. False or true

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Answer:

true

Explanation:

because if you find the right answer that proves the theory to be correct.

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3 years ago

Given the reaction: solid sodium reacts with chlorine gas to form solid sodium chloride How many moles of the product result fro

lyudmila [28]

Answer:

number of moles of NaCl produce = 12 mol

Explanation:

Firstly, we need to write the chemical equation of the reaction and balance it .

Na(s) + Cl2(g) → NaCl(s)

The balanced equation is as follows:

2Na(s) + Cl2(g) → 2NaCl(s)

1 mole(71 g) of chlorine produces 2 moles(117 g) of sodium chloride

6 mole of chlorine gas will produce ? mole of sodium chloride

cross multiply

number of moles of NaCl produce = 6 × 2

number of moles of NaCl produce = 12 moles

number of moles of NaCl produce = 12 mol

3 0

3 years ago

Calculate the molality of acetone in an aqueous solution with a mole fraction for acetone of 0.241. Answer in units of m.

Anit [1.1K]

Answer: The molality of solution is 17.6 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

$Molarity=\frac{n}{W_s}$

where,

n = moles of solute

$W_s$ = weight of solvent in kg

moles of acetone (solute) = 0.241

moles of water (solvent )= (1-0.241) = 0.759

mass of water (solvent )= $moles\times {\text {Molar Mass}}=0.759\times 18=13.7g=0.0137kg$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.241}{0.0137kg}=17.6mole/kg$

Therefore, the molality of solution is 17.6 mole/kg

3 0

3 years ago