Copper oxide(solid) + Sulphuric Acid (aqueous)-> Copper Sulphate (aqueous)+ Water(liquid)
In equation form:
CuO +H2SO4 -> CuSO4 + H2O
The colour change you will see is black to blue as Copper oxide is usually found as a black powder. Upon the reaction with sulphuric acid it will change to a cyan blue.
If you heat the made solution of copper sulphate, the water will evaporate and you will be left with white anhydrous copper sulphate crystals.
The N2H4 bond angle will be probably 109 degrees. Since, well,<span> it has a bent </span>trigonal pyramidal<span> geometry.</span>
Answer:
The correct answer is pOH= 11
Explanation:
From the aqueous acid-base equilibrium we know that
pH + pOH = 14
If we know pH, we can calculate pOH as follows:
pOH = 14 - pH
In this problem, the solution has a pH of 3, so:
pOH = 14 - 3 = 11
Answer:
John Newlands
Explanation:
he established the law of octaves
Answer:
Density, D = 2g/cm^3
Explanation:
Given the following data;
Length = 2cm
Width = 3cm
Height = 2cm
Mass = 24g
Density = ?
Volume of a rectangular solid (V) = Length × Weight × Height
Therefore, V = L× W × H
Substituting the values, we have;
V = 12cm
Density can be defined as the ratio of mass to volume i.e mass all over volume.
Mathematically, 
Substituting the values, we have;
<em>Density, D = 2g/cm^3</em>
Hence, the density of the rectangular solid is 2g/cm^3.
