Answer:
0 degree C
Explanation:
0 degree C = 32 degree F
0 degree F = -17.7778 degree C
Answer: It showed that all atoms contain electrons.
Explanation:
- J.J. Thomson's experiments inside a cathode ray tube in the presence of an electric field showed that all atoms contain tiny negatively charged subatomic particles "electrons".
- Also, Thomson's plum pudding model of the atom had negatively-charged electrons embedded within a positively-charged "soup."
- Furthermore, Rutherford's gold foil experiment showed that the atom is mostly empty space with a tiny positively-charged nucleus.
- Then, Rutherford proposed the nuclear model of the atom based on these results.
We are given –
- Mass of
is 57.1 g and we are asked to find number of moles present in 57.1 g of ![\bf N_2](https://tex.z-dn.net/?f=%20%5Cbf%20N_2)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\pink{\bf\longrightarrow { Molar \:mass \:of \: N_2:-} }](https://tex.z-dn.net/?f=%20%5Cpink%7B%5Cbf%5Clongrightarrow%20%20%7B%20Molar%20%5C%3Amass%20%5C%3Aof%20%5C%3A%20N_2%3A-%7D%20%20%7D)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf \twoheadrightarrow 14\times 2](https://tex.z-dn.net/?f=%20%5Cbf%20%20%5Ctwoheadrightarrow%2014%5Ctimes%202%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf \twoheadrightarrow 28](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctwoheadrightarrow%20%20%2028)
____________________
Now,Let's calculate the number of moles present in 57.1 g of ![\bf N_2](https://tex.z-dn.net/?f=%20%5Cbf%20N_2)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\purple{\bf\longrightarrow { No \:of \:moles = \dfrac{Given \:mass}{Molar\: mass}}}](https://tex.z-dn.net/?f=%20%5Cpurple%7B%5Cbf%5Clongrightarrow%20%20%7B%20No%20%5C%3Aof%20%5C%3Amoles%20%3D%20%5Cdfrac%7BGiven%20%5C%3Amass%7D%7BMolar%5C%3A%20mass%7D%7D%7D)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf \twoheadrightarrow \dfrac{57.1}{28}](https://tex.z-dn.net/?f=%20%5Cbf%20%20%20%5Ctwoheadrightarrow%20%5Cdfrac%7B57.1%7D%7B28%7D)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf \twoheadrightarrow 2.04\: moles](https://tex.z-dn.net/?f=%20%5Cbf%20%20%5Ctwoheadrightarrow%202.04%5C%3A%20moles)
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Charles law gives the relationship between temperature of gas and volume of gas.
It states that for a fixed amount of gas, temperature is directly proportional to volume of gas.
V / T = k
where V- volume , T - temperature and k - constant
![\frac{V1}{T1} = \frac{V2}{T2}](https://tex.z-dn.net/?f=%20%5Cfrac%7BV1%7D%7BT1%7D%20%3D%20%20%5Cfrac%7BV2%7D%7BT2%7D%20)
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
T1 = 250 °C + 273 = 523 K
T2 = 150 °C + 273 = 423 K
Substituting the values in the equation,
![\frac{310 mL}{523 K} = \frac{V}{423K}](https://tex.z-dn.net/?f=%20%5Cfrac%7B310%20mL%7D%7B523%20K%7D%20%3D%20%20%5Cfrac%7BV%7D%7B423K%7D%20)
V = 251 mL
the new volume is 251 mL