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Bond [772]
3 years ago
5

HELP PLEASE WILL GIVE  BRAINLIEST , the dark portion of the soil created by the decay of organic matters? is called?

Chemistry
2 answers:
NemiM [27]3 years ago
7 0

Answer is: humus.

Humus is the dark organic matter that forms in soil when dead plant and animal matter decays.

Microorganisms decompose the soil organic matter into inorganic minerals that the roots can absorb.

Humus can hold a lot of moisture (approximately 80–90% of its weight) and its dark color helps to warm cold soils.

natita [175]3 years ago
4 0

The answer is; Humus  

Humus is found in the topmost layer of the soil where there is decomposing organic matter. This layer of soil has a characteristic color of dark brown to black. This layer of soil also teems with microbial activity and organisms such as earthworms, fungi, and arthropods which  are  significant in the decomposition of the dead organic matter.


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KCl and KBr are both ionic solids. A mixture of KCl and KBr has a mass of 3.595 g. When this mixture is heated in the presence o
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Answer:

The percentage (by mass) of KBr in the original mixture was 33.1%.

Explanation:

The mixture of KCl and KBr has a mass of 3.595g, thus the sum of the moles of KCl (<em>x</em>) multiplied by it molar mass (74.5g/mol) and the moles of KBr (<em>y</em>) multiplied by it molar mass (119g/mol) is the total mass of the mixture:

x.74.5g/mol + y.119g/mol = 3.595g

Also, after the conversion of KBr into KCl, the total mass of 3.129 g is only from KCl moles, hence

\frac{3.129g}{74.5g/mol} = 0.042 moles

But the 0.042 moles came from the originals KCl and KBr moles, thus

x + y = 0.042moles

Now it is possible to propose a system of equations:

x.74.5g/mol + y.119g/mol = 3.595g

x + y = 0.042moles

Solving the system of equations,

x=0.032moles\\y=0.010 moles

0.010 moles of KBr multiplied it molar mass is

0.010molesx119g/mol = 1.19g

Therefore, the percentage (by mass) of KBr in the original mixture was:

\frac{1.19g}{3.595g}x100% = 33.1%%

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