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3 years ago

Drag the tiles to the correct boxes to complete the pairs.

Mathematics

1 answer:

Alborosie3 years ago

6 0

2⁻³² = (-2²)⁻⁶ • (2⁻⁵)⁻⁴

2⁻⁵ = (2²)² • (2³)⁻³

2⁸ = (-2⁻⁴)⁻² • (2²)⁰

1 = 2⁴ • (2²)⁻²

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Find the perimeter of the polygon with the given vertices x(-1,3) y(3,0) z(-1,-2)

Dvinal [7]

x(-1,3) y(3,0) z(-1,-2)

m = (3 + 1)/(0 - 3) = 4/-3 = -4/3

y - 3 = -4/3(x + 1)

y - 3 = -4/3x - 4/3

xy: y = -4/3x + 5/3

m = (0 + 2)/(3 + 1) = 2/4 = 1/2

y = 1/2(x - 3)

yz: y = 1/2x - 3/2

m = (3 + 2)/(-1 + 1) = 5/0 = undefined

y - 3 = undefined(x + 1)

xz: x = -1

xy: y = -4x/3 + 5/3

yz: y = x/2 - 3/2

xz: x = -1

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3 years ago

Factor the expression. d2 + 12d+ 36

Natali5045456 [20]

Answer:

the factored expression is

(d+6)(d+6) or (d+6)^2

Step-by-step explanation:

8 0

3 years ago

2x^2-4x-30 factored please. I m doing a test

bearhunter [10]

Answer:

2(x+3)(x−5)

Step-by-step explanation:

4 0

3 years ago

The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in <em>fourth</em> quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in <em>4th quadrant </em>so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

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3 years ago

Question 5 The enrollment at Davis Middle School dropped by 72 students over a 9 year period. What is the average yearly drop in

Mamont248 [21]

Answer:

it's 8

Step-by-step explanation:

just get 72 and divide it by 9 and that's the average over the 9 years.

7 0

2 years ago