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3 years ago

What is the equation of the line that passes through the point (-2, 1) and has a

Mathematics

1 answer:

juin [17]3 years ago

3 0

So i used the formula y=mx+b ; the equation should be y= -5/2 + 0.2

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What is the value of x in the triangle?

Ksivusya [100]

Answer:

X = 102

Step-by-step explanation:

41 + 37 + x = 180

78 + x = 180

X = 180 - 78 = 102

7 0

2 years ago

(39 points PLZ HELP)Find the sum of a finite geometric series. A ball is dropped from a height of 10 meters. Each time it bounce

erastovalidia [21]

So we need to find the sum of the first 5 terms.

You have told me that the first term is 10 meters, and that r = 0.5 per term.

With this knowledge, we can use the formula s_n=a₁((1-r^n)/(1-r)).

Plugging in the terms that we know...

s₅=10((1-0.5⁵)/(1-0.5))

s₅=10(0.96875/0.5)

s₅=10(1.9375)

s₅=19.375

With s₅, we can determine that the ball has traveled a total of 19.375 meters after 5 bounces.

3 0

3 years ago

Read 2 more answers

How do you solve number 29? Please step by step

trapecia [35]

Answer:

a) Junnie walked farther than Maurice

b) Junnie walked .62 miles farther than Maurice

Step-by-step explanation: Because speed times time equals distance, to find how far each person traveled you multiply their speed and time.

Distance=speed×time

Junnie:

2.5hrs×3.2mph=8 miles

Maurice:

1.8hrs×4.1mph=7.38 miles

8-7.38=.62 (the difference between the two)

3 0

3 years ago

Helppppp 3. Elaina's old bicycle had tires with a 12-inch diameter. Her new bicycle has tires with a 16-inch diameter. What is t

Setler [38]

I think the answer is b if it’s not my bad g

3 0

3 years ago

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A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

4 0

2 years ago